Sometimes, the most profound chemistry questions are the ones where absolutely nothing happens. This problem is a classic example of testing your fundamental understanding of reaction conditions and the nature of salts in an aqueous medium.
Analyzing the Setup
We are given two components to mix: ethyl acetate (CH3COOC2H5) and an aqueous solution of sodium chloride (NaCl).
Ethyl acetate is a common ester. In organic chemistry, esters are known to undergo a reaction called hydrolysis, where water breaks the ester bond to form a carboxylic acid and an alcohol. However, this reaction is notoriously slow in pure water. To make it happen at a measurable rate, we need a catalyst.
The Nature of Aqueous Sodium Chloride
Let's shift our focus to the other component: aqueous NaCl
Sodium chloride is the salt of a strong acid (HCl) and a strong base (NaOH).
When dissolved in water, it dissociates completely into Na+ and Cl− ions. Because both parent compounds are strong, neither the sodium ion nor the chloride ion has any tendency to react with water. This means they do not undergo salt hydrolysis. Consequently, the concentration of H+ and OH− ions in the solution remains equal to that of pure water, making the solution perfectly neutral with a pH of 7.
The Requirements for Ester Hydrolysis
For the hydrolysis of an ester to proceed, the medium must be either acidic (providing excess H+ ions) or basic (providing excess OH− ions)
These ions act as catalysts, lowering the activation energy required to break the ester linkage.
Since our aqueous NaCl solution is strictly neutral, it fails to provide the necessary acidic or basic environment.
The Final Verdict
Without the required catalyst, the ethyl acetate molecules and the sodium and chloride ions simply float around each other without interacting chemically
There is no bond breaking and no bond forming.
Therefore, the resultant solution is merely a physical mixture of the original reactants. The correct composition of the resultant solution is simply CH3COOC2H5+NaCl.