Sigma Percentile
JEE Main 2020
LEVELJEE Main

Animated Solution for Physics - Thermodynamics: Nitrogen gas is at temperature. The temperature (in K) at which the rms speed of a molecule would be equal to the rms speed of a molecule is ......... (Molar mass of gas is .)

Enter Numerical Value:

Visualized Solution

The Sigma Insight: Kinetic Theory of Gases

Solution Diagram

The Dance of the Molecules

Imagine you are observing two different gases in separate containers: Nitrogen () and Hydrogen (). The molecules are zipping around, colliding with each other and the walls of their containers. The speed at which they move is directly related to their temperature. But here's the catch—they don't all move at the exact same speed. Instead, we talk about their root mean square (rms) speed, which gives us a reliable measure of their average kinetic energy.
The formula for the rms speed is a beautiful piece of physics:
Here, is the universal gas constant, is the absolute temperature in Kelvin, and is the molar mass of the gas. Notice how the speed depends on two things: it increases with temperature () and decreases with molar mass (). Heavier molecules are sluggish, while lighter molecules are nimble and fast.

Setting Up the Duel

In our problem, we are told that the rms speed of the heavy Nitrogen molecules is exactly equal to the rms speed of the light Hydrogen molecules.
Let's substitute our formula into this equality:
By squaring both sides, the square roots vanish. The constant is present on both sides, so it gracefully cancels out, leaving us with a remarkably simple and elegant ratio:

The Temperature Trap

Before we rush into plugging in numbers, there is a classic trap waiting for us. The temperature of Nitrogen is given as . In thermodynamics, we must always use the absolute temperature scale (Kelvin).
Let's convert it:
Now we are ready. We know the molar mass of Nitrogen () is , and the molar mass of Hydrogen () is .

The Final Calculation

We need to find , the temperature of the Hydrogen gas. Rearranging our ratio gives:
Substitute the values we've gathered:
Rounding to the nearest integer, we get .
Think about what this means physically. Nitrogen is 14 times heavier than Hydrogen. To get those heavy Nitrogen molecules moving as fast as the light Hydrogen molecules, you have to heat the Nitrogen up to a scorching . Meanwhile, the nimble Hydrogen molecules can achieve that exact same speed while chilling at a freezing ! Physics is beautifully consistent.

Similar Questions

JEE Main 2002
LEVELJEE Main

At what temperature is the rms velocity of a hydrogen molecule equal to that of an oxygen molecule at ?

(A)
80 K
(B)
-73 K
(C)
3 K
(D)
20 K
JEE Main 2021
LEVELJEE Main

If the rms speed of oxygen molecules at is , find the rms speed of hydrogen molecules at .

(A)
640 m/s
(B)
40 m/s
(C)
80 m/s
(D)
332 m/s
JEE Main 2019
LEVELJEE Main

A mass of nitrogen gas is enclosed in a vessel at a temperature . Amount of heat transferred to the gas, so that rms velocity of molecules is doubled is about (Take, )

(A)
(B)
(C)
(D)
JEE Main 2021
LEVELJEE Main

The root mean square speed of molecules of a given mass of a gas at and atmosphere pressure is . The root mean square speed of molecules of the gas at and atmosphere pressure is . The value of will be ......... .

JEE Main 2019
LEVELJEE Main

For a given gas at pressure, rms speed of the molecules is at . At pressure and at , the rms speed of the molecules will be

(A)
(B)
(C)
(D)
JEE Main 2021
LEVELJEE Main

Consider a sample of oxygen behaving like an ideal gas. At , the ratio of root mean square (rms) velocity to the average velocity of gas molecule would be (Molecular weight of oxygen is ; )

(A)
(B)
(C)
(D)
LEVELJEE Main

The average translational energy and the rms speed of molecules in a sample of oxygen gas at K are J and m/s respectively. The corresponding values at K are nearly (assuming ideal gas behaviour)

(A)
J, m/s
(B)
J, m/s
(C)
J, m/s
(D)
J, m/s
LEVELJEE Main

The average translational kinetic energy of (molar mass 32) molecules at a particular temperature is . The translational kinetic energy of (molar mass 28) molecules in eV at the same temperature is

(A)
0.0015
(B)
0.003
(C)
0.048
(D)
0.768
JEE Main 2012
LEVELJEE Main

A mixture of 2 moles of helium gas (atomic mass = 4 amu) and 1 mole of argon gas (atomic mass = 40 amu) is kept at 300 K in a container. The ratio of the rms speeds is

(A)
0.32
(B)
0.45
(C)
2.24
(D)
3.16
JEE Main 2019
LEVELJEE Main

A mixture of 2 moles of helium gas (atomic mass = 4u) and 1 mole of argon gas (atomic mass = 40u) is kept at 300 K in a container. The ratio of their rms speeds is close to

(A)
0.32
(B)
2.24
(C)
3.16
(D)
0.45