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JEE Main 2020
LEVELJEE Main

Animated Solution for Chemistry - s and p-Block Elements: The metal mainly used in devising photoelectric cells is

Select Answer:

Visualized Solution

  • When light of sufficient energy strikes a metal surface, electrons are ejected.
  • The kinetic energy of the ejected electron is given by:
  • where is the threshold energy (work function) of the metal.

  • Threshold energy is directly related to the Ionization Energy (IE) of the metal.
  • Lower IE Lower
  • A lower means electrons are ejected more easily, and with higher kinetic energy for a given incident light.

  • Alkali metals (Group 1) have the lowest ionization energies in their respective periods.
  • As we move down the group, atomic size increases, and the outermost electron is further from the nucleus.
  • Order of Ionization Energy ():

  • Since Cesium (Cs) has the lowest ionization energy among the given options, it has the lowest threshold energy .
  • Order of :
  • Order of Kinetic Energy of emitted electrons:
  • Therefore, Cs is the best choice for photoelectric cells.

The Sigma Insight: Alkali Metals

Solution Diagram

The Magic of the Photoelectric Effect

Imagine you are shining a flashlight onto a piece of metal. If the light has enough energy, something incredible happens: it literally knocks electrons right out of the metal's surface! This phenomenon is known as the photoelectric effect, and it is the foundational principle behind solar panels, light sensors, and photoelectric cells.
Albert Einstein famously explained this using a beautifully simple equation:
Here, is the energy of the incoming light photon, and is the threshold energy (also known as the work function). The threshold energy is the absolute minimum energy required to break the electron free from the attractive grip of the metal's nucleus. Any leftover energy from the photon is transferred to the electron as kinetic energy (), allowing it to fly away.

The Quest for the Perfect Metal

If you were an engineer designing a highly efficient photoelectric cell, what kind of metal would you choose? You would want a metal that gives up its electrons very easily. In scientific terms, you want a metal with a very low ionization energy.
The lower the ionization energy, the lower the threshold energy (). A lower means that even low-energy light (like visible light) can trigger the photoelectric effect, and the ejected electrons will have a higher kinetic energy.

The Alkali Metals

Nature's Electron Donors
When we look at the periodic table, the Group 1 elements—the alkali metals—are famous for having the lowest ionization energies in their respective periods. They have a single electron in their outermost shell, and they are more than happy to get rid of it.
But within Group 1, which metal is the absolute best? Let's look at the trend as we move down the group from Lithium (Li) to Cesium (Cs):
As we move down the group, the atoms get progressively larger. The outermost electron in Cesium is much further away from the positively charged nucleus compared to the outermost electron in Lithium. Because of this increased distance and the shielding effect of inner electrons, the nucleus has a very weak grip on Cesium's outermost electron.
Consequently, the ionization energy decreases down the group:

The Undisputed King

Cesium
Because Cesium (Cs) has the lowest ionization energy among the stable alkali metals, it also has the lowest threshold energy ().
If we shine the exact same light on all these metals, the kinetic energy of the electrons flying out of Cesium will be the highest:
This makes Cesium incredibly sensitive to light. It can easily eject electrons even when exposed to ordinary visible light, making it the undisputed king and the best choice for devising highly responsive photoelectric cells!

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