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JEE Main 2017
LEVELJEE Main

Animated Solution for Chemistry - States of Matter: A metal crystallises in a face centred cubic structure. If the edge length of its unit cell is '', the closest approach between two atoms in metallic crystal will be

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Visualized Solution

Visualizing the FCC Face

  • In a Face-Centered Cubic (FCC) unit cell, atoms are present at all corners and at the centers of all faces.

The Face Diagonal

  • The atoms do not touch each other along the edges of the cube.
  • Instead, they touch each other along the face diagonal.

Length of Face Diagonal

  • Using Pythagoras theorem on the face of the cube:

Relating Diagonal to Radius

  • The face diagonal spans one full atom at the center and two half atoms at the corners.

Equating the Lengths

  • Equating the two expressions for the face diagonal:

Closest Approach Distance

  • The closest distance between two atoms is the distance between their centers when they are touching.

Final Calculation

  • Substitute the value of :

The Way Forward

  • What would be the closest approach in a Body-Centered Cubic (BCC) structure?

The Sigma Insight: Solid State

Solution Diagram

Analyzing the Setup

Imagine you are looking at a single face of a Face-Centered Cubic (FCC) unit cell. In this arrangement, atoms are located at all eight corners of the cube, and there is an additional atom sitting right in the center of each of the six faces.
Now, a common misconception is that the atoms touch each other along the edges of the cube. However, because of the atom sitting in the face center, the corner atoms are pushed slightly apart. They do not touch along the edge . Instead, they touch diagonally across the face.

The Master Equation

Let's focus on that face diagonal. If the edge length of our cubic unit cell is , we can easily find the length of the face diagonal using the Pythagoras theorem. The diagonal forms the hypotenuse of a right-angled triangle with two edges as its base and perpendicular.
Now, let's look at this same diagonal from the perspective of the atoms themselves. If we trace a line from one corner, through the face center, to the opposite corner, what do we cross? We cross the radius of the first corner atom, the full diameter of the face-centered atom, and the radius of the second corner atom.
Since both expressions represent the exact same physical length, we can equate them to find the relationship between the atomic radius and the edge length .

Final Calculation

The question asks for the closest approach between two atoms. In any crystal lattice, the closest approach is simply the distance between the centers of two atoms that are physically touching each other. Since the corner atom and the face-centered atom are touching, the distance between their centers is exactly .
Let's substitute the value of we just derived into our expression for the closest approach :
By rationalizing the denominator, we arrive at our final, elegant result:
This fundamental geometric relationship is the key to unlocking packing efficiency and density calculations for all FCC metals!

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