Sigma Percentile
JEE Main 2021
LEVELJEE Main

Animated Solution for Chemistry - Organic Chemistry: Match List I with List II. \begin{array}{ll} \textbf{List I} & \textbf{List II} \\ \text{(A) Chloroprene} & \text{(i)} \\ \text{(B) Neoprene} & \text{(ii)} \\ \text{(C) Acrylonitrile} & \text{(iii)} \\ \text{(D) Isoprene} & \text{(iv) } \mathrm{CH_2=CH-CN} \end{array} Choose the correct answer from the options given below.

Select Answer:

Visualized Solution

  • We need to match the common names of monomers and polymers in List I with their chemical structures in List II.

  • Chloroprene is the common name for .

  • Structure (ii) represents .

  • Neoprene is a synthetic rubber, which is a polymer of chloroprene. It undergoes addition polymerization.

  • Structure (iii) shows the repeating unit of poly(chloroprene).

  • Acrylonitrile is a vinyl compound with a cyanide group: .

  • Structure (iv) is exactly .

  • Isoprene is the monomer of natural rubber, chemically known as .

  • Structure (i) shows .

  • The correct matching is:

  • Always remember the difference between Isoprene (natural rubber monomer) and Chloroprene (synthetic rubber monomer).

The Sigma Insight: Polymers

Solution Diagram

Decoding the Language of Polymers

Welcome to a classic journey through polymer chemistry! In this problem, we are tasked with bridging the gap between the common names of famous industrial molecules and their exact chemical structures. This isn't just about memorization; it's about recognizing the functional groups that give these materials their unique properties.
Let's break down the list systematically.

Analyzing Chloroprene

We begin with Chloroprene. What exactly is it? Its formal IUPAC name is . This tells us we are dealing with a four-carbon chain containing two double bonds (a diene), with a chlorine atom attached to the second carbon.
When we scan the given structures, structure (ii) perfectly matches this description. You can clearly see the zig-zag butadiene backbone and the chlorine atom pointing upwards. Therefore, we can confidently say that (A) matches with (ii).

The Polymerization to Neoprene

Next up is Neoprene. Neoprene is a highly resilient synthetic rubber. But how is it made? It is simply the polymer formed from the chloroprene monomer we just identified.
During addition polymerization, the double bonds in the diene shift, allowing the molecules to link together into a continuous, long chain. Looking at our options, structure (iii) is the only one depicted as a polymer chain, indicated by the brackets and the subscript . Notice how the repeating unit still retains that signature chlorine atom. Thus, (B) matches with (iii).

Spotting Acrylonitrile

Moving on to Acrylonitrile. This is a very straightforward molecule. It consists of a vinyl group () attached directly to a cyanide, or nitrile, group ().
Looking at our choices, structure (iv) is explicitly written out as exactly this formula: . There are no complex skeletal structures to decode here! So, (C) clearly matches with (iv).

The Secret of Isoprene

Finally, we have Isoprene. This is a crucial molecule to remember because it is the fundamental building block (monomer) of natural rubber. Chemically, it is known as .
Notice how similar it is to chloroprene? The only difference is that the chlorine atom is replaced by a methyl group. By elimination, and by looking at structure (i), we see the familiar butadiene backbone with a single, unlabeled line pointing up. In skeletal structures, an unlabeled line represents a methyl () group. Therefore, (D) matches with (i).

Bringing It All Together

Let's compile our findings: - - - -
Checking our given options, this sequence perfectly aligns with option (b).
Pro Tip: Always remember the subtle difference between isoprene and chloroprene. One makes natural rubber, the other makes synthetic neoprene. Just swapping a methyl group for a chlorine atom completely changes the physical properties of the resulting polymer. Keep practicing these structures, and you'll spot them instantly in your exams!

Similar Questions

JEE Main 2020
LEVELJEE Main

The correct match between Item - I and Item - II is : \begin{array}{llll} & \textbf{Item - I} & & \textbf{Item - II} \\ \text{(A)} & \text{Natural rubber} & \text{(I)} & \text{1,3- butadiene + styrene} \\ \text{(B)} & \text{Neoprene} & \text{(II)} & \text{1,3- butadiene + acrylonitrile} \\ \text{(C)} & \text{Buna -N} & \text{(III)} & \text{Chloroprene} \\ \text{(D)} & \text{Buna -S} & \text{(IV)} & \text{Isoprene} \end{array}

(A)
(A)-(III), (B)-(IV), (C)-(I), (D)-(II)
(B)
(A)-(III), (B)-(IV), (C)-(II), (D)-(I)
(C)
(A)-(IV), (B)-(III), (C)-(II), (D)-(I)
(D)
(A)-(IV), (B)-(III), (C)-(I), (D)-(II)
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The correct match between Item-I and Item-II is

(A)
A III, B I, C IV, D II
(B)
A IV, B II, C I, D III
(C)
A III, B V, C I, D III
(D)
A III, B I, C II, D IV
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Buna-N synthetic rubber is a copolymer of

(A)
(B)
(C)
(D)
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The structure of neoprene is

(A)
(B)
(C)
(D)
JEE Main 2019
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The correct name of the following polymer is

(A)
polyisobutane
(B)
polytert-butylene
(C)
polyisoprene
(D)
polyisobutylene
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The structure of nylon-6 is

(A)
(B)
(C)
(D)
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On complete hydrogenation, natural rubber produces

(A)
ethylene-propylene copolymer
(B)
vulcanised rubber
(C)
polypropylene
(D)
polybutylene
LEVELBoard

Which of the following is fully fluorinated polymer?

(A)
PVC
(B)
Thiokol
(C)
Teflon
(D)
Neoprene
JEE Advanced 2022
LEVELJEE Main

Among the following, the correct statement(s) about polymers is(are)

* Multiple Correct Options
(A)
The polymerization of chloroprene gives natural rubber.
(B)
Teflon is prepared from tetrafluoroethene by heating it with persulphate catalyst at high pressures.
(C)
PVC are thermoplastic polymers.
(D)
Ethene at 350-570 K temperature and 1000-2000 atm pressure in the presence of a peroxide initiator yields high density polythene.
JEE Main 2021
LEVELJEE Main

Match List-I with List-II. Choose the most appropriate match

(A)
(A)-(ii), (B)-(i), (C)-(iv), (D)-(iii)
(B)
(A)-(iii), (B)-(iv), (C)-(ii), (D)-(i)
(C)
(A)-(iii), (B)-(i), (C)-(iv), (D)-(ii)
(D)
(A)-(ii), (B)-(iv), (C)-(i), (D)-(iii)