The Freundlich adsorption isotherm is a fundamental empirical relationship that describes how the quantity of a gas adsorbed by a solid surface varies with pressure at a constant temperature. In this problem, we are given experimental data plotted as a straight line, and we need to extract the physical constants to find the extent of adsorption at a specific pressure.
The Freundlich isotherm is mathematically expressed as:
mx=Kp1/n
where
x is the mass of the gas adsorbed,
m is the mass of the adsorbent,
p is the equilibrium pressure, and
K and
n are empirical constants that depend on the nature of the adsorbate and adsorbent at a given temperature.
To make this equation easier to analyze experimentally, we take the logarithm on both sides:
logmx=logK+n1logp
Notice how this logarithmic equation perfectly mirrors the equation of a straight line, y=mx+c.
If we plot logmx on the y-axis and logp on the x-axis, we get a straight line where:
- The slope of the line is n1.
- The y-intercept is logK.
The problem states that the slope of this graph is
2. Therefore:
n1=2
The y-intercept is given as
0.4771. Therefore:
logK=0.4771
We are also given that
log3=0.4771. By comparing these two, we can immediately deduce that:
K=3
Now that we have our constants, we can find the value of
mx at a pressure of
p=4 atm. Let's substitute these values back into the original Freundlich equation:
mx=Kp1/n
mx=3×(4)2
mx=3×16
mx=48