Sigma Percentile
JEE Main 2011
LEVELJEE Main

Animated Solution for Physics - Optics: A light ray travelling in glass medium is incident on glass-air interface at an angle of incidence . The reflected () and transmitted () intensities, both as function of , are plotted. The correct sketch is

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Visualized Solution

\text{Reflection and Transmission}

  • \text{When light travels from a denser medium (glass) to a rarer medium (air), it undergoes both reflection and transmission.}

\text{Normal Incidence } (\theta = 0^\circ)

  • \text{At normal incidence, the reflection coefficient is not zero.}
  • R = \left(\frac{n_1 - n_2}{n_1 + n_2}\right)^2 > 0
  • T = 1 - R < 100\%

\text{Increasing Angle of Incidence}

  • \text{As } \theta \text{ increases, the reflected intensity } R \text{ increases, and the transmitted intensity } T \text{ decreases.}

\text{Total Internal Reflection}

  • \text{At the critical angle } \theta_c = \sin^{-1}\left(\frac{n_2}{n_1}\right)\text{, Total Internal Reflection (TIR) occurs.}
  • \text{For } \theta \ge \theta_c:
  • R = 100\%
  • T = 0\%

\text{Analyzing the Graphs}

  • \text{Only graph (c) correctly shows:}
  • 1. R > 0 \text{ and } T < 100\% \text{ at } \theta = 0^\circ
  • 2. R = 100\% \text{ and } T = 0\% \text{ for } \theta \ge \theta_c

The Sigma Insight: Refraction and Total Internal Reflection

Solution Diagram

The Boundary of Two Worlds

Imagine a light ray travelling from a denser medium, like glass, into a rarer medium, like air.
When it hits the boundary, it doesn't just pass through seamlessly.
A part of the light energy is reflected back into the glass, and the remaining portion is transmitted into the air.
This fundamental behavior is governed by the laws of reflection and refraction, and it sets the stage for a fascinating interplay between the reflected intensity and the transmitted intensity .

The Myth of Perfect Transmission

Let's think about what happens when the light hits the surface exactly straight on, at an angle of incidence .
Is all the light transmitted? No!
Even at normal incidence, a small fraction of light is always reflected due to the difference in refractive indices of the two media.
Mathematically, the reflection coefficient at normal incidence is given by .
Because $n_1 eq n_2$, is strictly greater than zero.
Consequently, the transmitted intensity must be strictly less than .
This crucial detail means that on our graph, the curve for must start slightly above zero, and the curve for must start slightly below .

The Tipping Point

Total Internal Reflection
As we increase the angle of incidence , the light ray tilts further away from the normal.
What happens to the intensities?
The reflected ray gets progressively stronger, while the transmitted ray gets weaker.
Eventually, we reach a very special angle called the critical angle, denoted by .
At this exact point, something magical happens: Total Internal Reflection (TIR)!
The transmitted ray completely vanishes, meaning drops to exactly .
Simultaneously, all the light energy is now reflected back into the glass, so hits a perfect .
For any angle , the light remains completely trapped inside the glass, so stays at and stays at .

Decoding the Graphs

Now, let's look at our options and apply what we've learned.
We need a graph where starts above zero and starts below at .
We also need to smoothly reach and to smoothly drop to at the critical angle , which occurs well before .
If you look closely at the given options, graphs (a), (b), and (d) all incorrectly show starting at exactly and starting at exactly .
Only graph (c) perfectly captures this beautiful physical reality, showing the correct initial values and the smooth transition to Total Internal Reflection!

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