Sigma Percentile
JEE Main 2024 (29 Jan Shift 2)
LEVELJEE Main

Animated Solution for Mathematics - Differentiation: Let . Then at , the value of is equal to

Select Answer:

Visualized Solution

Simplify the Function

  • Given:
  • Target: at
  • Property:

First Derivative

Second Derivative Setup

  • Quotient Rule:

Simplify

Evaluate Constants at

  • Substitute

Calculate at

Calculate at

Compute

  • Common denominator is

Final Calculation

  • Target:
  • Value
  • Final Answer

The Sigma Insight: Higher Order Derivatives

Analyzing the Setup

Imagine standing before a massive, intimidating mountain. If you try to climb it straight up the sheer face, you will likely fall. But if you look for the winding path, the climb becomes a journey.
We are given the function:
If you jump straight into the quotient rule, you are climbing the sheer face. Instead, let's use the power of logarithmic properties. We know that .
This simple identity transforms our function into:
Now, the mountain is just a gentle hill.

The First Derivative

Now that we have simplified, let's find . We apply the chain rule to each term.
The derivative of is , and the derivative of is . When we combine these, we get:
Factoring out , we find a common denominator of , which is . The numerator simplifies beautifully to .
Thus, the first derivative is:

The Second Derivative

Now, we face the second derivative, . We must differentiate using the quotient rule: .
Here, and . The derivatives are and . Plugging these in, we get:
Simplifying the numerator, we distribute the to get , and the second term becomes . Combining these, we get , or .
So, the second derivative is:

The Final Evaluation

We are at the finish line. We need to evaluate at .
First, let's find the value of . Then .
Now, substitute these into our derivatives: For , we get:
For , we get:
Now, compute :
Converting to a common denominator of , we get:
Finally, multiply by :
The cancellation is perfect. The final answer is 736.

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