Analyzing the Setup
Welcome, fellow traveler in the world of calculus. Today, we are going to dismantle a problem that, at first glance, might seem like a tangled mess of exponentials and derivatives.
In the realm of JEE Advanced, the most intimidating equations are often just simple concepts wearing a disguise. Our target is the differential equation (1+e2x)(dxdy+y)=1.
Phase 1
The Standard Form
When you see a differential equation, your first instinct should be to classify it. The structure dxdy+y is a massive hint that this is a Linear Differential Equation (LDE).
To make this explicit, we divide the entire equation by (1+e2x):
Now, compare this to the standard LDE form: dxdy+P(x)y=Q(x). Here, P(x)=1 and Q(x)=1+e2x1.
Phase 2
The Magic of the Integrating Factor
We need the key to unlock this machine: the Integrating Factor (I.F.). The formula is elegant and powerful: I.F.=e∫P(x)dx.
Since our P(x) is just 1, the integral is trivial: ∫1dx=x. Thus, our Integrating Factor is ex.
When we multiply the entire equation by ex, the left-hand side collapses into the derivative of a product: dxd(y⋅ex). This turns a sum of terms into a single, manageable derivative.
Phase 3
The Integration
Multiplying our equation by ex, we obtain:
Note that e2x is simply (ex)2. If we let t=ex, then dt=exdx, and the integral transforms into ∫1+t21dt.
This is a standard integral resulting in tan−1(t). Substituting back, we get:
Phase 4
Finding the Constant
We have the general solution, but we need the specific curve that passes through (0,2π). Plugging in x=0 and y=2π:
Since e0=1 and tan−1(1)=4π, the equation becomes 2π=4π+C. Solving for the constant, we find C=4π.
Our particular solution is defined as:
Phase 5
The Final Crescendo
The question asks for limx→∞exy(x). We have the expression for exy(x) ready for evaluation.
We take the limit as x→∞ of tan−1(ex)+4π. As x approaches infinity, ex approaches infinity, and tan−1(∞) approaches 2π.
Therefore, the final limit is: