Analyzing the Setup
We are tasked with finding the number of non-singular matrices M in the set S, where:
The variables a,b,c are restricted to the set {ω,ω2}, where ω is a complex cube root of unity. Recall that ω3=1 and 1+ω+ω2=0.
The Vanishing Act
A matrix is non-singular if and only if its determinant is non-zero. We calculate the determinant by expanding along the first row:
det(M)=1(1−cω)−a(ω−cω2)+b(ω2−ω2)
Observe that the coefficient of b is (ω2−ω2)=0. This implies that the determinant is independent of the value of b.
Since b can be either ω or ω2, there are 2 possible choices for b that do not affect the non-singularity of the matrix.
The Factorization
With the b term eliminated, the determinant simplifies to:
We can group the terms to factor the expression:
Factoring out (1−aω), we obtain the elegant result:
For the matrix to be non-singular, we require $\det(M)
eq 0$. This condition is satisfied if and only if $(1 - a\omega)
eq 0$ and $(1 - c\omega)
eq 0$.
The Constraints
We evaluate the constraints on a and c given that a,c∈{ω,ω2}.
If a=ω2, then aω=ω3=1. This results in (1−aω)=(1−1)=0, which makes the determinant zero. Therefore, a must be ω.
Similarly, if c=ω2, then cω=ω3=1, leading to (1−cω)=0. Thus, c must also be ω.
The Final Count
We have determined that a has 1 valid choice (ω) and c has 1 valid choice (ω). As established earlier, b has 2 valid choices (ω or ω2).
The total number of non-singular matrices is the product of the number of choices for each variable:
The total number of non-singular matrices is 2.