Analyzing the Setup
Imagine a 3×3 matrix M where each entry xi∈{0,1,2}. We are tasked with finding the number of such matrices that satisfy the condition tr(MTM)=7.
The trace of the product MTM is defined as the sum of the squares of all entries in the matrix M. If we denote the entries as x1,x2,…,x9, the condition is expressed as:
The Constraint Game
Since each xi∈{0,1,2}, the possible values for xi2 are {0,1,4}. We must partition the integer 7 into exactly nine parts using only these values.
We analyze the possible combinations of squares that sum to 7:
Case I
Using the value 4
If we include one 4 (which corresponds to an entry of 2), the remaining eight squares must sum to 7−4=3. To achieve a sum of 3 using only 0s and 1s, we must select exactly three 1s and five 0s.
The set of squares is {4,1,1,1,0,0,0,0,0}. The number of distinct matrices is determined by the number of permutations of these nine items:
1!×3!×5!9!=1×6×120362880=504
Case II
Excluding the value 4
If we do not use the value 4, we must sum to 7 using only 0s and 1s. This requires exactly seven 1s and two 0s.
The set of squares is {1,1,1,1,1,1,1,0,0}. The number of distinct matrices is:
Final Calculation
Having exhausted all possible partitions of 7 under the given constraints, we sum the results from both cases.
The total number of such matrices is:
By identifying the trace property, we transformed a complex matrix problem into a straightforward combinatorial counting exercise.