Sigma Percentile
JEE Main 2021 (24 February Shift 1)
LEVELJEE Main

Animated Solution for Mathematics - Matrices and Determinants: Let be any matrix with entries from the set . The maximum number of such matrices, for which the sum of diagonal elements of is seven, is

Enter Numerical Value:

Visualized Solution

Defining Matrix

  • Let
  • Entries

The Trace of

  • Sum of diagonal elements of
  • Given:

Analyzing Possible Values

  • Possible values of
  • Possible values of
  • We need to solve:

Case I: Using a

  • Case I: One entry is , three entries are , and five entries are .
  • Squares:

Calculating Case I Matrices

  • Number of matrices for Case I =

Case II: Using only s

  • Case II: Seven entries are and two entries are .
  • Squares:

Calculating Case II Matrices

  • Number of matrices for Case II =

Final Summation

  • Total number of matrices = Case I + Case II

The Sigma Insight: Algebraic Operations on Matrices

Solution Diagram

Analyzing the Setup

Imagine a matrix where each entry . We are tasked with finding the number of such matrices that satisfy the condition .
The trace of the product is defined as the sum of the squares of all entries in the matrix . If we denote the entries as , the condition is expressed as:

The Constraint Game

Since each , the possible values for are . We must partition the integer into exactly nine parts using only these values.
We analyze the possible combinations of squares that sum to :

Case I

Using the value
If we include one (which corresponds to an entry of ), the remaining eight squares must sum to . To achieve a sum of using only s and s, we must select exactly three s and five s.
The set of squares is . The number of distinct matrices is determined by the number of permutations of these nine items:

Case II

Excluding the value
If we do not use the value , we must sum to using only s and s. This requires exactly seven s and two s.
The set of squares is . The number of distinct matrices is:

Final Calculation

Having exhausted all possible partitions of under the given constraints, we sum the results from both cases.
The total number of such matrices is:
By identifying the trace property, we transformed a complex matrix problem into a straightforward combinatorial counting exercise.

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