The Roller Coaster of Calculus
Imagine you are standing at the start of a roller coaster track. The track is defined by the function f(x)=2x3−9x2+12x+5, and your ride is strictly limited to the section between x=0 and x=3.
Your goal is to find the highest peak (M) and the lowest valley (m) on this specific stretch of track. This is the essence of the Extreme Value Theorem, which states that for any continuous function on a closed interval, an absolute maximum and minimum must exist.
The Hunt for Critical Points
To find these extrema, we must examine two types of locations: the boundaries of our interval and the points where the track levels off. The boundaries are simply x=0 and x=3.
To find the "level" points, we calculate the derivative of the function to determine where the slope of the tangent line is zero:
f′(x)=dxd(2x3−9x2+12x+5)=6x2−18x+12
Setting this derivative to zero identifies the critical points where the roller coaster is momentarily flat:
Dividing by 6, we obtain the simplified quadratic equation x2−3x+2=0. Factoring this yields (x−1)(x−2)=0, providing critical points at x=1 and x=2.
Since both x=1 and x=2 fall within our interval [0,3], they are both valid candidates for our search.
The Final Audit
We now perform a final audit by evaluating the original function f(x) at each of our four candidates: the boundaries (x=0,3) and the critical points (x=1,2).
1. At
x=0:
f(0)=2(0)3−9(0)2+12(0)+5=5
2. At
x=1:
f(1)=2(1)3−9(1)2+12(1)+5=2−9+12+5=10
3. At
x=2:
f(2)=2(2)3−9(2)2+12(2)+5=16−36+24+5=9
4. At
x=3:
f(3)=2(3)3−9(3)2+12(3)+5=54−81+36+5=14
Comparing the results {5,10,9,14}, the absolute maximum M is 14 (at x=3), and the absolute minimum m is 5 (at x=0).
The Final Calculation
The objective is to find the difference M−m. Using our determined values:
By systematically checking the boundaries and the critical points, we have successfully navigated the roller coaster of this cubic function. The final result is 9.