Animated Solution for Mathematics - Conic Sections: Let f(x)=x2+9,g(x)=x−9x and a=f∘g(10),b=g∘f(3). If e and l denote the eccentricity and the length of the latus rectum of the ellipse ax2+by2=1, then 8e2+l2 is equal to.
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Visualized Solution
Understanding the Composite Function a
Given: f(x)=x2+9
Given: g(x)=x−9x
We need to find a=f(g(10)).
This means mapping 10 through g, then through f.
Evaluating the Inner Function g(10)
Substitute x=10 into g(x):
g(10)=10−910
Computing g(10)
g(10)=110
g(10)=10
Substituting into the Outer Function
Now, substitute g(10)=10 into f(x):
a=f(10)
a=102+9
Computing the Value of a
a=100+9
a=109
Understanding the Composite Function b
Next, we need to find b=g(f(3)).
This means mapping 3 through f, then through g.
Evaluating the Inner Function f(3)
Substitute x=3 into f(x):
f(3)=32+9
f(3)=9+9=18
Computing the Value of b
Substitute f(3)=18 into g(x):
b=g(18)=18−918
b=918=2
Constructing the Ellipse Equation
The standard equation of the ellipse is ax2+by2=1.
Substituting a=109 and b=2:
109x2+2y2=1
Formula for Eccentricity Squared
For an ellipse where denominator of x2 > denominator of y2:
e2=1−major axis2minor axis2
e2=1−ab
Computing e2
Substitute a=109 and b=2:
e2=1−1092
e2=109109−2=109107
Formula for Length of Latus Rectum
The length of the latus rectum l is given by:
l=major axis2×minor axis2
l=a2b
Computing l2
Substitute a=109 and b=2:
l=1092(2)=1094
Squaring both sides:
l2=10916
Setting up 8e2+l2
We need to find the value of 8e2+l2.
Substitute e2=109107 and l2=10916:
8e2+l2=8(109107)+10916
Final Computation
8×107=856
8e2+l2=109856+10916
8e2+l2=109872
8e2+l2=8
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The Sigma Insight: Foci, Directrices, and Eccentricity
Solution Diagram
The Beauty of Composite Functions and Elliptical Geometry
Welcome, fellow traveler on the JEE journey. Today, we are not just solving a problem; we are peeling back the layers of a mathematical onion.
We have a composite function problem that leads us into the elegant world of conic sections. It might look like a simple algebra exercise at first, but it requires precision and a deep understanding of how functions and geometry dance together.
Analyzing the Setup
We start with two functions: f(x)=x2+9 and g(x)=x−9x. Our mission is to find two constants, a and b, which will define our ellipse.
Think of composite functions like a relay race. In a=f(g(10)), the number 10 is the runner. It first passes through the g function, and the result of that sprint is then handed off to the f function.
Let us evaluate the inner function first:
g(10)=10−910=110=10
Now, we take this result and feed it into f(x):
a=f(10)=102+9=100+9=109
Our first constant is locked in: a=109.
Now, for b=g(f(3)). We start with:
f(3)=32+9=9+9=18
Now, we pass this 18 into g(x):
b=g(18)=18−918=918=2
We have successfully navigated the algebra: a=109 and b=2.
The Geometry of the Ellipse
With a and b in hand, our ellipse equation becomes:
109x2+2y2=1
This is a classic horizontal ellipse. Because 109>2, the major axis is clearly along the x-axis. In the language of conic sections, the semi-major axis is 109 and the semi-minor axis is 2.
Now, we need the eccentricity e. The formula for a horizontal ellipse is e2=1−ab. Substituting our values:
e2=1−1092=109109−2=109107
Next, the latus rectum l. The standard length is semi-major2×(semi-minor)2. With our values:
l=1092(2)=1094
The question asks for l2. So, we square this value:
l2=10916
Final Calculation
We have arrived at the final hurdle: 8e2+l2. We have our components ready: e2=109107 and l2=10916.
Let us assemble them:
8(109107)+10916
Multiplying 8 by 107 gives us 856. So, we have:
109856+10916=109872
If you perform the division, you will find that 109×8=872. The final result is exactly 8.