Sigma Percentile
JEE Main 2024 (04 Apr Shift 2)
LEVELJEE Advanced

Animated Solution for Mathematics - Differentiation: Let be a thrice differentiable function such that and . Then, the minimum number of zeros of is _______

Enter Numerical Value:

Visualized Solution

Analyze

  • Given expression:
  • Goal: Identify if this is a derivative of a simpler function.
  • Hint: Look for product rule patterns.

Define Parent Function

  • Let
  • We will differentiate this to see if it leads to our expression.

First Derivative

Second Derivative

Plotting Given Values of

  • Given:
  • Let's plot these points on the coordinate plane.

Zeros of via IVT

  • is a zero.
  • and zero in .
  • and zero in .
  • and zero in .
  • Total zeros of .

Zeros of via Rolle's Theorem

  • Rolle's Theorem: Between any two roots of , there is at least one root of .
  • Since has roots, has at least roots.
  • These correspond to the horizontal tangents.

Total Zeros of

  • A product is zero if either factor is zero.
  • Zeros of
  • Minimum zeros of .

Zeros of

  • Apply Rolle's Theorem to .
  • If has zeros, has at least zeros.
  • Minimum zeros of .

Zeros of

  • Apply Rolle's Theorem to .
  • Minimum zeros of .
  • Since , the minimum number of zeros is .

The Sigma Insight: Mean Value Theorems

Solution Diagram

Analyzing the Setup

We are given a thrice differentiable function with the following values: , , , , and .
Our objective is to determine the minimum number of zeros for the expression .

The Detective Work

Recognizing the Pattern
At first glance, the expression appears complex. However, we can identify a "parent" function by observing the structure of its derivatives. Let us define a function .
Applying the product rule to , we find the first derivative:
Differentiating once more to find , we apply the product rule to both terms:
Combining the like terms, we arrive at the elegant result:
Thus, the expression we are investigating is exactly the second derivative of .

Mapping the Terrain

The Intermediate Value Theorem
We analyze the roots of using the Intermediate Value Theorem (IVT). We are given .
Between the given points, the function changes sign as follows: 1. In , changes from to , implying at least one zero. 2. In , changes from to , implying at least one zero. 3. In , changes from to , implying at least one zero.
Including the known zero at , has at least distinct zeros.

The Chain Reaction

Rolle's Theorem
We now apply Rolle's Theorem to determine the zeros of the derivatives. If has zeros, then must have at least zeros, located between the consecutive zeros of .
Recall that . The zeros of occur whenever or .
Since the zeros of and are distinct, possesses at least zeros.

The Final Descent

Reaching the Goal
We apply Rolle's Theorem iteratively to the function . Since has at least zeros, its first derivative must have at least zeros.
Applying Rolle's Theorem once more to , we conclude that must have at least zeros.
The expression is equivalent to . Therefore, the minimum number of zeros for the given expression is 5.

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