Analyzing the Architecture of the Binomial Expansion
We are tasked with analyzing the expression (x2/3+x32)30 to find a term of the form βx−α, where β is a natural number and α is the smallest positive value possible. This requires a systematic decomposition of the binomial structure.
The General Term
Every binomial expansion follows a specific rhythm defined by the general term formula:
Tr+1=(rn)an−rbr
In this structure, our parameters are
n=30,
a=x2/3, and
b=2x−3. Substituting these into the formula, we establish the foundation:
Tr+1=(r30)(x2/3)30−r(2x−3)r
The Algebraic Dance
To simplify the expression, we apply the laws of exponents. First, we process the powers of
x:
(x2/3)30−r=x20−32r
Next, we distribute the power
r to the second term:
(2x−3)r=2r⋅x−3r
Combining these components by adding the exponents of
x, we obtain:
x20−32r⋅x−3r=x20−32r−3r
Finding a common denominator of
3, the exponent simplifies to:
20−32r+9r=20−311r
Thus, the general term is expressed as:
Tr+1=(r30)2r⋅x20−311r
The Constraint
The problem defines our target term as
βx−α. By comparing this to our derived expression, we identify the exponent of
x as
−α:
−α=20−311r⟹α=311r−20
We are given the constraint that
α must be the smallest positive number. Therefore, we set the condition
α>0:
311r−20>0
Solving for
r:
311r>20⟹11r>60⟹r>1160≈5.45
Final Deduction
Since
r must be an integer, the smallest integer satisfying
r>5.45 is
r=6. We now calculate the value of
α using this integer:
α=311(6)−20=22−20=2
By navigating the constraints and the algebra, we have determined that the smallest positive value for α is 2.