Analyzing the Setup
We are given the set A={−4,−3,−2,0,1,3,4}. This set contains 7 distinct elements. A relation R on A×A is defined by the conditions b=∣a∣ or b2=a+1.
Our goal is to determine the minimum number of elements that must be added to R to make it both reflexive and symmetric.
Mapping the Existing Territory
First, we identify the elements currently in R based on the given conditions. For the condition b=∣a∣, we test each a∈A:
(−4,4),(−3,3),(0,0),(1,1),(3,3),(4,4)
Note that for a=−2, ∣−2∣=2, but $2
otin A$. Thus, this pair is excluded.
For the condition b2=a+1, we test each a∈A:
If a=0, then b2=1, which gives b=1 (since 1∈A). Thus, (0,1)∈R.
If a=3, then b2=4, which gives b=−2 (since −2∈A). Thus, (3,−2)∈R.
The current set
R is:
R={(−4,4),(−3,3),(0,0),(1,1),(3,3),(4,4),(0,1),(3,−2)}
The Quest for Reflexivity
A relation is reflexive if (a,a)∈R for all a∈A. Currently, we have (0,0),(1,1),(3,3), and (4,4).
We are missing the diagonal elements for
−4,−3, and
−2. To satisfy reflexivity, we must add the following
3 elements:
(−4,−4),(−3,−3),(−2,−2)
The Mirror of Symmetry
A relation is symmetric if for every (a,b)∈R, the point (b,a) must also be in R. We examine our current set R (including the reflexive additions):
(−4,4) requires (4,−4).
(−3,3) requires (3,−3).
(0,1) requires (1,0).
(3,−2) requires (−2,3).
The diagonal elements are already symmetric. Thus, we must add these 4 new pairs to ensure symmetry.
Final Calculation
To make the relation reflexive, we added 3 elements. To make the relation symmetric, we added 4 elements.
The total number of elements that must be added to the relation
R is:
3+4=7
The minimum number of elements required to complete the network is 7.