Animated Solution for Physics - Electromagnetic Waves: Intensity of sunlight is observed as 0.092 Wm−2 at a point in free space. What will be the peak value of magnetic field at that point? (ε0=8.85×10−12 C2N−1m−2)
Select Answer:
Visualized Solution
The Electromagnetic Wave
I=0.092 W/m2
ε0=8.85×10−12 C2N−1m−2
c=3×108 m/s
Intensity of EM Wave
I=21ε0cE02
E0=cB0
Master Equation for B0
I=21ε0c(cB0)2
I=21ε0c3B02
B0=ε0c32I
Substituting the Values
B0=8.85×10−12×(3×108)32×0.092
B0=8.85×10−12×27×10240.184
Simplifying the Denominator
B0=238.95×10120.184
B0=0.00077×10−12
Calculating the Peak Magnetic Field
B0=7.7×10−16
B0=2.77×10−8 T
The Way Forward
E0=cB0
E0≈8.31 V/m
Energy is equally shared!
00:00 / 00:00
The Sigma Insight: Characteristics of Electromagnetic Waves
Solution Diagram
Riding the Electromagnetic Wave
Finding the Magnetic Field from Sunlight's Intensity
Imagine sunlight streaming through the vast emptiness of space. It's not just light; it's a dynamic, oscillating electromagnetic wave carrying energy across the cosmos. We are given the intensity of this sunlight, which is exactly 0.092 W/m2. This means that every second, 0.092 Joules of energy crosses a one-square-meter area perpendicular to the wave. Our mission is to uncover the peak magnetic field hidden within this wave.
The Master Equation
How is the intensity of an electromagnetic wave related to its fields? The intensity I is given by the formula:
I=21ε0cE02
Here, ε0 is the permittivity of free space, c is the speed of light, and E0 is the peak electric field. But wait, we need the magnetic field! Remember that the electric and magnetic fields in an EM wave are intimately connected. The peak electric field is simply the speed of light times the peak magnetic field:
E0=cB0
Let's substitute this relationship directly into our intensity equation. This gives us the intensity entirely in terms of the magnetic field:
I=21ε0c(cB0)2=21ε0c3B02
Rearranging this, we get a beautiful master equation for the peak magnetic field:
B0=ε0c32I
The Calculation
Now, let's carefully plug in the numbers. We have 2×0.092 in the numerator. In the denominator, we have ε0, which is 8.85×10−12, multiplied by the cube of the speed of light, (3×108)3, which is 27×1024.
B0=8.85×10−12×27×10242×0.092
Let's simplify the denominator first. Multiplying 8.85 by 27 gives 238.95. Combining the powers of ten (−12 and 24) gives 1012. Dividing 0.184 by this massive number yields 0.00077×10−12.
B0=0.00077×10−12
We can rewrite this elegantly to make taking the square root straightforward:
B0=7.7×10−16
The square root of 10−16 is 10−8, and the square root of 7.7 is approximately 2.77. So, our peak magnetic field is:
B0=2.77×10−8 T
The Profound Symmetry
Did you notice how incredibly small the magnetic field is compared to the electric field? It's smaller by a factor of the speed of light! Yet, fascinatingly, both fields carry exactly the same amount of energy in an electromagnetic wave. The energy density of the electric field (21ε0E2) is perfectly equal to the energy density of the magnetic field (2μ0B2). They share the wave's energy perfectly 50-50, a beautiful symmetry in the laws of physics.