Analyzing the Setup
Imagine you are standing in a vast, open field, holding a triangle ABC. You know the basics: the sum of the angles is π, and the sides are connected by the Law of Sines.
We are given a trigonometric equation: 3sinx−4sin3x−k=0. At first glance, this looks like a standard, perhaps even intimidating, cubic equation in terms of sinx.
However, the expression 3sinx−4sin3x is the triple angle identity for sine, sin3x. By recognizing this, we transform the complex cubic into the elegant statement:
Connecting Algebra to Geometry
The problem states that A and B satisfy this equation. This means A and B are the roots of sin3x=k, giving us the relations sin3A=k and sin3B=k.
Since both are equal to k, we set them equal to each other: sin3A=sin3B. Bringing them to one side, we obtain:
We now apply the sum-to-product identity, sinC−sinD=2cos(2C+D)sin(2C−D). Applying this to our equation, we get:
2cos(23A+3B)sin(23A−3B)=0
The Trapdoor and the Solution
We have a product of two terms equal to zero. We are given that A>B, which implies A−B>0.
Because A and B are angles of a triangle, their difference is constrained such that the term sin(23(A−B)) cannot be zero. We can safely discard this factor.
This leaves us with the cosine term:
For the cosine of an angle to be zero, the angle itself must be an odd multiple of 2π. In the context of our triangle, we set:
Final Calculation
With a quick algebraic simplification, we cancel the denominators to find that 3(A+B)=π, which implies:
We know the fundamental property of any triangle: A+B+C=π. Substituting our value for A+B, we get:
Solving for C, we find the final result:
C=32π