Sigma Percentile
JEE Advanced 1990
LEVELJEE Main

Animated Solution for Mathematics - Trigonometry: In a triangle , angle is greater than angle . If the measures of angles and satisfy the equation , then the measure of angle is

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Visualized Solution

Triangle Setup

  • Let's consider a triangle .
  • The angles are , , and .
  • We are given that angle .

The Trigonometric Equation

  • We are given the equation:
  • Rearranging the terms:

Multiple Angle Identity

  • Recall the triple angle identity for sine:
  • Substituting this back, our equation simplifies to:

Substituting the Roots

  • The problem states that angles and satisfy this equation.
  • This means and are roots of .
  • Therefore, we can write:

Equating the Expressions

  • Since both expressions equal :
  • Bringing them to one side:

Sum-to-Product Transformation

  • Apply the trigonometric formula:
  • Applying this to our equation:

Checking the Constraints

  • For the product to be zero, at least one factor must be zero.
  • Let's check the sine factor:
  • We know , which means .
  • Also, , so is not a multiple of .
  • Therefore, .

Setting Cosine to Zero

  • Since the sine factor is non-zero, the cosine factor must be zero.
  • The cosine of an angle is zero when the angle is an odd multiple of .
  • For angles in a triangle, the relevant value is .

Finding the Sum of Angles A and B

  • Equating the angle to :
  • Canceling the from the denominators:
  • Dividing by :

The Triangle Angle Sum

  • We need to find the measure of angle .
  • Recall the fundamental property of any triangle:

Calculating Angle C

  • Substitute the value of into the sum equation:
  • Isolate :

The Sigma Insight: Trigonometric Ratios and Identities

Solution Diagram

Analyzing the Setup

Imagine you are standing in a vast, open field, holding a triangle . You know the basics: the sum of the angles is , and the sides are connected by the Law of Sines.
We are given a trigonometric equation: . At first glance, this looks like a standard, perhaps even intimidating, cubic equation in terms of .
However, the expression is the triple angle identity for sine, . By recognizing this, we transform the complex cubic into the elegant statement:

Connecting Algebra to Geometry

The problem states that and satisfy this equation. This means and are the roots of , giving us the relations and .
Since both are equal to , we set them equal to each other: . Bringing them to one side, we obtain:
We now apply the sum-to-product identity, . Applying this to our equation, we get:

The Trapdoor and the Solution

We have a product of two terms equal to zero. We are given that , which implies .
Because and are angles of a triangle, their difference is constrained such that the term cannot be zero. We can safely discard this factor.
This leaves us with the cosine term:
For the cosine of an angle to be zero, the angle itself must be an odd multiple of . In the context of our triangle, we set:

Final Calculation

With a quick algebraic simplification, we cancel the denominators to find that , which implies:
We know the fundamental property of any triangle: . Substituting our value for , we get:
Solving for , we find the final result:

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