LEVELJEE Main
Visualized Solution
The Sigma Insight: Optical Instruments
The Anatomy of a Compound Microscope
To truly appreciate the genius behind a compound microscope, we must understand its dual-lens architecture. A compound microscope employs two convex lenses to achieve massive magnification: the objective lens (the one closest to the object) and the eyepiece (the one you look through).
The objective lens has a very short focal length () and a small aperture. Its primary mission is to capture light from a tiny specimen and project a magnified, real image deep inside the microscope tube.
The Role of the Objective Lens
For the microscope to work, the intermediate image created by the objective lens must be real. Why? Because a real image is physically projected into space, allowing the second lens (the eyepiece) to use it as an actual object.
To achieve this, where should we place the specimen?
If we place the object inside the focal length (), the convex lens acts like a simple magnifying glass, producing a virtual, erect image on the same side. This is useless for a compound microscope because the image wouldn't travel down the tube to the eyepiece.
Therefore, the object is placed just outside the focal point, specifically between and .
The Ray Diagram and Image Formation
Let's trace the geometry:
1. Ray 1: A ray from the top of the object travels parallel to the principal axis. Upon striking the convex objective lens, it refracts and passes exactly through the principal focus () on the other side.
2. Ray 2: A second ray from the top of the object passes straight through the optical center of the lens. It continues its journey completely undeviated.
These two rays converge and physically intersect on the other side of the lens, beyond . Because the light rays actually meet, the resulting image is real. Because it forms below the principal axis, it is inverted. And crucially, because the object was placed between and , the geometry dictates that the image is enlarged.
(Note: Some textbook solutions mistakenly state that the object is placed "between its focus and lens". As we've just proved, placing the object there would yield a virtual image, which is incorrect for the objective lens of a compound microscope. The object must be strictly beyond the focus!)
The Final Verdict
The objective lens of a compound microscope forms an intermediate image that is real and enlarged. This perfectly sets the stage for the eyepiece to act as a simple magnifier, taking this real image and blowing it up into the massive, virtual final image that your eye sees.
Thus, the correct option is (c).
Similar Questions
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The focal lengths of the objective and the eyepiece of a compound microscope are 2.0 cm and 3.0 cm respectively. The distance between the objective and the eyepiece is 15.0 cm. The final image formed by the eyepiece is at infinity. The two lenses are thin. The distance in cm of the object and the image produced by the objective, measured from the objective lens, are respectively
(A)
2.4 and 12.0
(B)
2.4 and 15.0
(C)
2.0 and 12.0
(D)
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In a compound microscope, the magnified virtual image is formed at a distance of 25 cm from the eye-piece. The focal length of its objective lens is 1 cm. If the magnification is 100 and the tube length of the microscope is 20 cm, then the focal length of the eye-piece lens (in cm) is ......... .
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A compound microscope consists of an objective lens of focal length cm and an eye piece of focal length cm with a separation of cm. The distance between an object and the objective lens, at which the strain on the eye is minimum is cm. The value of is …… .
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If we need a magnification of 375 from a compound microscope of tube length 150 mm and an objective of focal length 5 mm, the focal length of the eyepiece should be close to
(A)
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(C)
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* Multiple Correct Options
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the distance between the objective and the eyepiece is
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(C)
the image of the planet is inverted
(D)
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Given below are two statements: one is labelled as Assertion (A) and the other is labelled as Reason (R). Assertion (A) For a simple microscope, the angular size of the object equals the angular size of the image. Reason (R) Magnification is achieved as the small object can be kept much closer to the eye than 25 cm and hence, it subtends a large angle. In the light of the above statements, choose the most appropriate answer from the options given below.
(A)
A is true but R is false.
(B)
Both A and R are true but R is not the correct explanation of A.
(C)
Both A and R are true and R is the correct explanation of A.
(D)
A is false but R is true.
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An object viewed from a near point distance of 25 cm, using a microscopic lens with magnification 6, gives an unresolved image. A resolved image is observed at infinite distance with a total magnification double the earlier using an eyepiece along with the given lens and a tube of length 0.6 m, if the focal length of the eyepiece is equal to ......... cm.
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An observer looks at a distance tree of height 10 m with a telescope of magnifying power of 20. To the observer the tree appears
(A)
10 times taller
(B)
10 times nearer
(C)
20 times taller
(D)
20 times nearer
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Some laws/processes are given in Column I. Match these with the physical phenomena given in Column II.
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An astronomical telescope has an angular magnification of magnitude for far objects. The separation between the objective and the eyepiece is and the final image is formed at infinity. The focal length of the objective and the focal length of the eyepiece are
(A)
and
(B)
and
(C)
and
(D)
and
