Sigma Percentile
JEE Main 2026 (21 January Shift 1)
LEVELJEE Main

Animated Solution for Mathematics - Complex Numbers: If , then the value of is:

Select Answer:

Visualized Solution

Analyze the Equation

  • Given equation:
  • We need to evaluate:

Identify the Roots and

  • Roots of are the complex cube roots of unity.
  • Let or .
  • and

Properties of

  • Property 1: (Periodicity of 3)
  • Property 2:

Simplify

  • Divide by :
  • Geometrically, .

Define the General Term

  • Let the term be .
  • Since , the expression will repeat its values every 3 terms.

Evaluate for

  • For :

Evaluate for

  • For :

Evaluate for

  • For :

Observe the Periodicity

  • The sequence of values for is
  • The pattern repeats every 3 terms.

Identify Multiples of 3

  • Multiples of 3 in the range are: .
  • Total number of such terms .
  • Each of these terms contributes to the sum.

Count Remaining Terms

  • Total terms .
  • Number of non-multiples of 3 .
  • Each of these terms contributes to the sum.

Final Summation

  • Total Sum

The Sigma Insight: Cube Roots and nth Roots of Unity

Solution Diagram

Analyzing the Setup

Imagine you are standing at the edge of a mathematical cliff, staring down at a massive, intimidating summation:
At first glance, it looks like a brute-force nightmare. But in the world of JEE Advanced, we never use a sledgehammer when a scalpel will do.
The equation is our scalpel. This is the signature of the complex cube roots of unity. When you see this, your mind should immediately jump to the unit circle in the complex plane.
The roots, and , are not just numbers; they are vectors of length , separated by degrees.

The Magic of Simplification

Before we touch the summation, let us simplify the base. If we take and divide every term by , we get .
This reveals the hidden truth: . This is the heartbeat of the problem.
Geometrically, adding the vectors and cancels out their imaginary components, leaving us with a real value of . This simple realization is the key that unlocks the entire structure.

The Rhythm of the Sequence

Now, let us define our general term . Because , the powers of cycle every three steps.
This means our sequence of terms will also cycle. Let us calculate the first three:
For , we have .
For , we have .
For , we have .
The pattern is . It repeats every three terms.

The Final Summation

We have terms in total. The pattern repeats as long as we have full cycles of three.
How many full cycles are there? divided by is with a remainder of .
This means we have full cycles of , which equals per cycle. So, .
But wait, we have one term left over, the th term. Since the pattern starts over, the th term is the same as the st term, which is .
Adding this to our total, we get . The complexity has melted away, leaving behind the pure, crystalline elegance of the answer: 145.

Similar Questions

JEE Main 2006
LEVELJEE Main

If , where is complex number, then the value of is

(A)
18
(B)
54
(C)
6
(D)
12
JEE Main 2022 (25 July Shift 1)
LEVELJEE Main

If are the roots of the equation , then is equal to.

(A)
-4
(B)
-1
(C)
1
(D)
4
JEE Main 2022 (29 June Shift 2)
LEVELJEE Main

Let be a root of the equation . Then the value of is equal to:

(A)
1
(B)
(C)
(D)
JEE Main 2022 (26 June Shift 2)
LEVELJEE Main

If , then is equal to \_\_\_\_\_.

JEE Main 2025 April
LEVELJEE Main

Let be a solution of , and for some and in , . If , then is equal to

(A)
3
(B)
11
(C)
7
(D)
8
JEE Main 2024 (27 Jan Shift 1)
LEVELJEE Main

If satisfies the equation and , , then is equal to

JEE Main 2010
LEVELJEE Main

If and are the roots of the equation , then

(A)
(B)
1
(C)
2
(D)
JEE Advanced 1996
LEVELJEE Main

The value of the expression , where is an imaginary cube root of unity, is

JEE Main 2025 April
LEVELJEE Main

If is a root of the equation and , then is equal to

JEE Main 2021 (February)
LEVELJEE Main

The sum of power of the roots of the equation is