Analyzing the Setup
Imagine you are standing at the edge of a mathematical cliff, staring down at a massive, intimidating summation:
At first glance, it looks like a brute-force nightmare. But in the world of JEE Advanced, we never use a sledgehammer when a scalpel will do.
The equation x2+x+1=0 is our scalpel. This is the signature of the complex cube roots of unity. When you see this, your mind should immediately jump to the unit circle in the complex plane.
The roots, ω and ω2, are not just numbers; they are vectors of length 1, separated by 120 degrees.
The Magic of Simplification
Before we touch the summation, let us simplify the base. If we take x2+x+1=0 and divide every term by x, we get x+1+x1=0.
This reveals the hidden truth: x+x1=−1. This is the heartbeat of the problem.
Geometrically, adding the vectors ω and ω2 cancels out their imaginary components, leaving us with a real value of −1. This simple realization is the key that unlocks the entire structure.
The Rhythm of the Sequence
Now, let us define our general term Tk=(xk+xk1)4. Because x3=1, the powers of x cycle every three steps.
This means our sequence of terms Tk will also cycle. Let us calculate the first three:
For k=1, we have T1=(x+x1)4=(−1)4=1.
For k=2, we have T2=(x2+x21)4=(ω2+ω)4=(−1)4=1.
For k=3, we have T3=(x3+x31)4=(1+1)4=24=16.
The pattern is 1,1,16. It repeats every three terms.
The Final Summation
We have 25 terms in total. The pattern 1,1,16 repeats as long as we have full cycles of three.
How many full cycles are there? 25 divided by 3 is 8 with a remainder of 1.
This means we have 8 full cycles of (1+1+16), which equals 18 per cycle. So, 8×18=144.
But wait, we have one term left over, the 25th term. Since the pattern starts over, the 25th term is the same as the 1st term, which is 1.
Adding this to our total, we get 144+1=145. The complexity has melted away, leaving behind the pure, crystalline elegance of the answer: 145.