Here,
ω and
ω2 represent the complex cube roots of unity. These roots satisfy the fundamental properties:
ω3=1
1+ω+ω2=0
To find the product
xyz, we substitute the given expressions:
xyz=(a+b)(aω+bω2)(aω2+bω)
We keep the first term
(a+b) constant and focus on expanding the product of the latter two brackets:
(aω+bω2)(aω2+bω)
Expanding this product term by term yields:
a2ω3+abω2+abω4+b2ω3
Using the property
ω3=1, we simplify the expression. Note that
ω4=ω3⋅ω=ω:
a2(1)+abω2+abω+b2(1)
=a2+ab(ω2+ω)+b2
Substituting the identity
ω+ω2=−1 into the middle term:
=a2+ab(−1)+b2
=a2−ab+b2
Now, we multiply this result by the first bracket
(a+b) that we set aside earlier:
xyz=(a+b)(a2−ab+b2)
Recognizing this as the standard algebraic identity for the sum of two cubes, we conclude:
xyz=a3+b3