Sigma Percentile
JEE Advanced 1978
LEVELBoard

Animated Solution for Mathematics - Complex Numbers: If and where and are the complex cube roots of unity, show that .

Visualized Solution

Identifying the Roots and

  • Let the complex cube roots of unity be and .
  • Given: and .
  • Key Properties:
  • 1.
  • 2.

Setting up the Product

  • Substitute in the product expression:

Expanding the Complex Terms

  • Multiply the last two brackets:

Simplifying Powers of

  • Use and :

Applying the Sum Property

  • Substitute :

The Final Identity

  • Combine with the first factor:
  • Using the identity :
  • Hence Proved.

The Sigma Insight: Cube Roots and nth Roots of Unity

Analyzing the Setup

We are given the variables:
Here, and represent the complex cube roots of unity. These roots satisfy the fundamental properties:
From the second property, we derive the identity , which will serve as our primary tool for simplification.

The Master Equation

To find the product , we substitute the given expressions:
We keep the first term constant and focus on expanding the product of the latter two brackets:
Expanding this product term by term yields:

Simplifying the Expression

Using the property , we simplify the expression. Note that :
Substituting the identity into the middle term:

Final Calculation

Now, we multiply this result by the first bracket that we set aside earlier:
Recognizing this as the standard algebraic identity for the sum of two cubes, we conclude:

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