Animated Solution for Mathematics - Matrices and Determinants: If the system of linear equations x−4y+7z=g, 3y−5z=h, −2x+5y−9z=k is consistent, then :
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Visualized Solution
System of Linear Equations
Plane P1:x−4y+7z=g
Plane P2:3y−5z=h
Plane P3:−2x+5y−9z=k
Condition: The system is consistent.
Coefficient Matrix Determinant
Coefficient Matrix A=10−2−4357−5−9
Let's find the determinant Δ=∣A∣.
Expanding Δ
Expanding along the first column (C1):
Δ=135−5−9−0+(−2)−437−5
Calculating Δ
Δ=1(−27−(−25))−2(20−21)
Δ=1(−2)−2(−1)
Δ=−2+2=0
Condition for Consistency
Since Δ=0, the system has either no solution or infinite solutions.
Given it is consistent, it must have infinite solutions.
Geometrically, the planes intersect along a common line.
Linear Dependency of Equations
For infinite solutions, the equations must be linearly dependent.
There exist constants a,b,c (not all zero) such that:
aP1+bP2+cP3=0
Finding Dependency: x-coefficients
Let's equate the coefficients of x to zero:
a(1)+b(0)+c(−2)=0
a−2c=0⟹a=2c
Finding Dependency: y-coefficients
Equating the coefficients of y to zero:
a(−4)+b(3)+c(5)=0
Substitute a=2c:
−4(2c)+3b+5c=0
Solving for b
−8c+3b+5c=0
−3c+3b=0
3b=3c⟹b=c
Choosing Values for a,b,c
We have a=2c and b=c.
Let's choose c=1.
Then a=2 and b=1.
The dependency is: 2P1+1P2+1P3=0
Verifying z-coefficients
Let's quickly verify this with the z coefficients:
2(7)+1(−5)+1(−9)
14−5−9=0 (Verified!)
Applying Dependency to Constants
For the system to be consistent, the same linear dependency must apply to the constant terms on the Right Hand Side.
a(g)+b(h)+c(k)=0
Substitute a=2,b=1,c=1:
2g+h+k=0
Final Answer
Final Relation: 2g+h+k=0
This matches Option (2).
Key Takeaway: If Δ=0 and the system is consistent, the linear dependency in the LHS coefficients perfectly mirrors the dependency in the RHS constants.
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The Sigma Insight: Solution of System of Linear Equations (Matrix Method and Cramer's Rule)
Solution Diagram
Analyzing the Setup
Imagine you are standing in a vast, three-dimensional space. You are surrounded by three massive, flat sheets—these are our planes, defined by the equations P1:x−4y+7z=g, P2:3y−5z=h, and P3:−2x+5y−9z=k.
The problem asks us to find the condition under which this system is consistent. This means these three planes, in their infinite expanse, must share at least one common point.
The Heartbeat of the System
The Determinant
Before we dive into the geometry, we need to check the 'heartbeat' of our system: the determinant of the coefficient matrix A. We extract the coefficients of x,y, and z to form the matrix:
A=10−2−4357−5−9
We calculate the determinant Δ=∣A∣ by expanding along the first column, which is the most efficient path due to the zero in the second row. The calculation unfolds as:
Δ=135−5−9−0+(−2)−437−5
Δ=1(−27−(−25))−2(20−21)=1(−2)−2(−1)=−2+2=0
The Moment of Truth
Infinite Solutions
When Δ=0, the system is at a crossroads. It either has no solution (the planes never meet) or infinitely many solutions (the planes intersect along a common line).
Since the problem guarantees consistency, we know we are in the realm of infinite solutions. Geometrically, this means our three planes are not independent; they are locked in a dance where one is essentially a combination of the others.
The Secret Handshake
Linear Dependency
To find the condition on g,h, and k, we must uncover the 'linear dependency'—the hidden relationship between the equations. We assume there exist constants a,b, and c such that aP1+bP2+cP3=0.
Let's break this down by coefficients:
For x: a(1)+b(0)+c(−2)=0⟹a=2c.
For y: a(−4)+b(3)+c(5)=0. Substituting a=2c, we get −4(2c)+3b+5c=0, which simplifies to −8c+3b+5c=0, or 3b=3c, meaning b=c.
The Grand Finale
By setting c=1, we find a=2 and b=1. Our dependency is 2P1+1P2+1P3=0. We verify this with the z-coefficients: 2(7)+1(−5)+1(−9)=14−5−9=0.
It works perfectly! For the system to be consistent, this same dependency must apply to the constants g,h, and k on the right-hand side:
a(g)+b(h)+c(k)=0⟹2g+h+k=0
And there it is! The elegance of linear algebra reveals that the relationship between the planes is mirrored in their constants. The final condition for consistency is 2g+h+k=0.