Analyzing the Setup
Imagine you are standing in a three-dimensional space, looking at three distinct planes. In a typical system of linear equations, these planes intersect at a single point, giving you a unique solution.
But today, we are exploring a special case: the system has infinitely many solutions. This means these planes are not just meeting at a point; they are dancing together, intersecting along a common line or perhaps even coinciding entirely. This is the geometric soul of the problem we are solving today.
The Cramer's Rule Toolkit
When we face a system of equations like kx+y+2z=1, 3x−y−2z=2, and −2x−2y−4z=3, our first instinct should be to reach for our most reliable tool: Cramer's Rule.
We know that for a system to have infinitely many solutions, the main determinant Δ must be zero. But remember, this is only the first gate.
We must also ensure that the determinants Δx, Δy, and Δz are all zero. If Δ=0 but one of the others is not, the planes are parallel and never meet, leaving us with no solution at all.
The Vanishing Act
Let us construct our main determinant Δ using the coefficients of x,y,z:
As we expand this along the first row, we get:
Δ=k((−1)(−4)−(−2)(−2))−1((3)(−4)−(−2)(−2))+2((3)(−2)−(−1)(−2))
Calculating the terms inside, we find:
Δ=k(4−4)−1(−12−4)+2(−6−2)
Suddenly, the k term vanishes because 4−4=0. We are left with 0+16−16=0. This confirms that Δ is zero regardless of k. The system is poised for infinite solutions, but we still need to find the specific k that makes it happen.
Hunting the Unknown
Since Δ didn't help us find k, we pivot to the secondary condition: Δy=0. We construct Δy by replacing the second column of our original matrix with the constants from the right-hand side:
Expanding this along the first row, we get:
Δy=k((2)(−4)−(−2)(3))−1((3)(−4)−(−2)(−2))+2((3)(3)−(2)(−2))
Simplifying this, we have:
Δy=k(−8+6)−1(−12−4)+2(9+4)
This reduces to Δy=−2k+16+26, or simply Δy=−2k+42.
The Final Revelation
Now, we set Δy=0 to satisfy the condition for infinite solutions:
With a simple algebraic step, 2k=42, we arrive at k=21.
It is a beautiful moment of clarity. We didn't just solve an equation; we navigated the constraints of 3D space to find the exact condition where these planes align perfectly. Keep this logic in your heart: Δ=0 is the necessary condition, but the consistency of the system is the true test.