Analyzing the General Term
To begin, we define the general term Tr+1 of the binomial expansion (xn+x52)7. Using the Binomial Theorem, the expression is given by:
Tr+1=7Cr⋅(xn)7−r⋅(x52)r
By simplifying this expression, we separate the numerical coefficients from the variable powers:
Tr+1=(7Cr⋅2r)⋅xn(7−r)−5r
The exponent of x, which we denote as P(r), is defined by the function:
The Coefficient Game
We are interested in the sum of coefficients of the positive powers of x. Let Cr=7Cr⋅2r represent the coefficient of the (r+1)-th term. We calculate these values for r=0,1,2,3,4:
For r=0: C0=7C0⋅20=1⋅1=1
For r=1: C1=7C1⋅21=7⋅2=14
For r=2: C2=7C2⋅22=21⋅4=84
For r=3: C3=7C3⋅23=35⋅8=280
For r=4: C4=7C4⋅24=35⋅16=560
Summing these coefficients, we find:
Establishing Boundary Conditions
Since the sum of coefficients for terms with positive powers is exactly 939, the terms from r=0 to r=4 must correspond to positive powers of x. This implies two critical constraints on n.
First, the term at r=4 must have a positive power (P(4)>0):
n(7−4)−5(4)>0⇒3n−20>0⇒n>320≈6.66
Second, the term at r=5 must not have a positive power (P(5)≤0), otherwise, its coefficient would have been included in the sum:
n(7−5)−5(5)≤0⇒2n−25≤0⇒n≤12.5
Final Calculation
Combining these inequalities, we obtain the range for n:
The integers n that satisfy this condition are 7,8,9,10,11, and 12. The sum of these values is: