Animated Solution for Physics - Work, Energy, and Power: If the kinetic energy of a moving body becomes four times of its initial kinetic energy, then the percentage change in its momentum will be
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Visualized Solution
m,v,p,K
Let the mass of the body be m and its velocity be v.
K=2mp2
Kinetic Energy (K) and Momentum (p) are related as:
K=2mp2⟹p=2mK
K2=4K1
Given that final kinetic energy is 4 times the initial kinetic energy:
K2=4K1
p1p2=K1K2
Since mass m is constant, p∝K.
p1p2=K1K2
p1p2=K14K1
Substituting K2=4K1:
p1p2=K14K1
p2=2p1
p1p2=4=2
⟹p2=2p1
%Δp=p1p2−p1×100%
Percentage change in momentum is given by:
%Δp=p1p2−p1×100%
%Δp=100%
%Δp=p12p1−p1×100%
%Δp=p1p1×100%=100%
What if %Δp=100%?
What if the momentum is increased by 100%, what will be the percentage increase in kinetic energy?
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The Sigma Insight: Kinetic Energy, Potential Energy and Power
Solution Diagram
The Setup
Energy and Momentum
Imagine a block of mass m gliding smoothly across a frictionless surface with a velocity v. This simple motion carries two fundamental physical quantities: momentum (p) and kinetic energy (K).
Momentum is the measure of the "quantity of motion," defined simply as p=mv. Kinetic energy, on the other hand, is the energy of that motion, given by K=21mv2.
The Mathematical Bridge
To solve problems efficiently, we need a direct bridge between these two quantities. By substituting v=mp into the kinetic energy equation, we get the master relation:
K=2mp2
This equation is incredibly powerful. It tells us that for a body of constant mass, the kinetic energy is directly proportional to the square of its momentum (K∝p2). Conversely, the momentum is directly proportional to the square root of the kinetic energy (p∝K).
Calculating the Change
The problem presents a fascinating scenario: the kinetic energy of the body becomes four times its initial value. Let's write this mathematically:
K2=4K1
Since we know that p∝K, we can set up a ratio to find the new momentum:
p1p2=K1K2
Now, we substitute our given condition into the ratio:
p1p2=K14K1
The K1 terms cancel out beautifully, leaving us with:
p1p2=4=2
This means the final momentum is exactly double the initial momentum (p2=2p1).
The Final Percentage
We are asked to find the percentage change in momentum. The standard formula for percentage change is:
%Δp=p1p2−p1×100%
Let's plug in our new momentum p2=2p1:
%Δp=p12p1−p1×100%
%Δp=p1p1×100%=100%
The momentum has increased by exactly 100%. This makes perfect physical sense: doubling the momentum (2×) results in quadrupling the kinetic energy (22=4×).