Analyzing the Setup
Welcome, future engineer. Today, we are not just solving a problem; we are exploring the elegant dance between two curves. When we look at the equations x=y4 and xy=k, we aren't just looking at algebraic expressions.
We are looking at a sideways parabola and a rectangular hyperbola, two distinct geometric entities meeting at a point P(x,y). The problem asks us to consider the case where these curves cut at right angles—a condition known as orthogonality.
This is a beautiful concept. It means that at the very moment they touch, their paths are perpendicular. Let us unravel this step by step.
The Calculus of Slopes
To understand the intersection, we must understand the direction of each curve at point P. We need the slopes of the tangents.
For our first curve, x=y4, we differentiate with respect to y:
Since the slope m1 is defined as dxdy, we take the reciprocal:
Now, consider the second curve, xy=k. To find its slope m2, we use implicit differentiation with respect to x:
We now have the "DNA" of both curves at the point of intersection.
The Orthogonality Condition
If two curves are orthogonal, their tangents are perpendicular. In the coordinate plane, this implies that the product of their slopes must be −1.
Setting m1⋅m2=−1, we substitute our expressions:
The negative signs cancel out, and the y terms simplify to y2 in the denominator. We are left with the following constraint:
The Algebraic Finale
We need to evaluate the expression (4k)6. Since k=xy, our target is (4xy)6, which expands to 46x6y6.
We know from our first curve that x=y4. Substituting this into our constraint 4xy2=1:
Now, we express x6 in terms of y. Since x=y4, then x6=(y4)6=y24.
Substituting this into our target expression 46x6y6:
We rewrite y30 as (y6)5. Substituting y6=41 into the expression:
The final result is 4.