The Beauty of Trigonometric Symmetry
Welcome, fellow traveler on the path to JEE mastery. Today, we are not just solving a trigonometric identity; we are uncovering a hidden symmetry.
When you see a condition like α+β+γ=2π, your brain might immediately jump to complex expansions. But wait—take a breath. Look at the options.
They are all in terms of half-angles. This is the universe whispering the secret to you: the problem is already half-solved if you just listen to the structure.
Phase 1
The Half-Angle Transformation
We start with the given condition: α+β+γ=2π. Since the target expressions involve 2α, 2β, and 2γ, we must transform our world.
Dividing the entire equation by 2 gives us:
This is our new foundation. It is elegant, simple, and perfectly aligned with the trigonometric identities we are about to deploy.
Phase 2
The Strategic Shift
Now, we need to bring the tangent function into play. But we cannot just take the tangent of all three terms at once. We need a strategy.
Let us isolate two terms on the left and push the third to the right:
Why do this? Because we know exactly how to handle tan(π−θ). It is a bridge to simplicity.
Phase 3
The Tangent Identity
Taking the tangent of both sides, we get tan(2α+2β)=tan(π−2γ). On the left, we use the addition identity:
tan(A+B)=1−tanAtanBtanA+tanB
Substituting A=2α and B=2β, the left side becomes:
1−tan2αtan2βtan2α+tan2β
On the right, the identity tan(π−θ)=−tanθ transforms tan(π−2γ) into −tan2γ. We have successfully reduced the complexity.
Phase 4
The Algebraic Dance
Now, we equate them:
1−tan2αtan2βtan2α+tan2β=−tan2γ
To clear the fraction, we cross-multiply. Be careful here—this is where the battle is often won or lost. We get:
tan2α+tan2β=−tan2γ(1−tan2αtan2β)
Expanding the right side and distributing the negative sign, we obtain:
tan2α+tan2β=−tan2γ+tan2αtan2βtan2γ
Finally, moving −tan2γ to the left, we arrive at the beautiful conclusion:
tan2α+tan2β+tan2γ=tan2αtan2βtan2γ
This is the elegance of mathematics. We started with a simple sum and ended with a profound relationship between the sum and the product of tangents. You have conquered this problem!