Sigma Percentile
JEE Main 2021, 20 July Shift-I
LEVELJEE Main

Animated Solution for Physics - Kinematics: If and are two vectors satisfying the relation . Then, the value of will be

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Visualized Solution

  • Let the angle between and be .

  • Given:

The Sigma Insight: Dot and Cross Products

Solution Diagram

The Dance of Dot and Cross Products

Vectors are the language of physics, allowing us to describe quantities that have both magnitude and direction. Two of the most fundamental operations we can perform on vectors are the dot product and the cross product.
The dot product, defined as , tells us how much of one vector goes in the direction of the other. It's a measure of parallelism. On the other hand, the magnitude of the cross product, , tells us how much of one vector is perpendicular to the other.

The Master Equation

In this problem, we are given a beautiful symmetric condition: the dot product equals the magnitude of the cross product.
Substituting our definitions into this equation, we get:
Assuming our vectors are non-zero, we can divide both sides by . This leaves us with a simple trigonometric equation:
Dividing by , we find that . The only angle between and that satisfies this is . This means our vectors are perfectly balanced between being parallel and perpendicular!

The Geometry of Vector Difference

Now that we know the angle between the vectors, we need to find the magnitude of their difference, . Geometrically, if we place and tail-to-tail, is the vector pointing from the tip of to the tip of .
Alternatively, we can think of it as adding and . Using the law of cosines for vector addition, the magnitude of the difference is given by:

Final Calculation

We simply substitute our known angle of into the formula:
Since , we have:
Simplifying the fraction gives us . Thus, our final expression is:
This elegant result perfectly captures the geometric relationship between the two vectors.

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