Animated Solution for Physics - Kinematics: If A and B are two vectors satisfying the relation A⋅B=∣A×B∣. Then, the value of ∣A−B∣ will be
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Visualized Solution
Visualizing the Vectors
Let the angle between A and B be θ.
Dot Product
A⋅B=ABcosθ
Cross Product
∣A×B∣=ABsinθ
Equating the Products
Given: A⋅B=∣A×B∣
⟹ABcosθ=ABsinθ
Finding θ
cosθ=sinθ
⟹tanθ=1
⟹θ=45∘
Vector Difference Formula
∣A−B∣=A2+B2−2ABcosθ
Substituting θ
∣A−B∣=A2+B2−2ABcos(45∘)
Final Answer
cos(45∘)=21
∣A−B∣=A2+B2−2AB
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The Sigma Insight: Dot and Cross Products
Solution Diagram
The Dance of Dot and Cross Products
Vectors are the language of physics, allowing us to describe quantities that have both magnitude and direction. Two of the most fundamental operations we can perform on vectors are the dot product and the cross product.
The dot product, defined as A⋅B=ABcosθ, tells us how much of one vector goes in the direction of the other. It's a measure of parallelism. On the other hand, the magnitude of the cross product, ∣A×B∣=ABsinθ, tells us how much of one vector is perpendicular to the other.
The Master Equation
In this problem, we are given a beautiful symmetric condition: the dot product equals the magnitude of the cross product.
A⋅B=∣A×B∣
Substituting our definitions into this equation, we get:
ABcosθ=ABsinθ
Assuming our vectors are non-zero, we can divide both sides by AB. This leaves us with a simple trigonometric equation:
cosθ=sinθ
Dividing by cosθ, we find that tanθ=1. The only angle between 0∘ and 180∘ that satisfies this is θ=45∘. This means our vectors are perfectly balanced between being parallel and perpendicular!
The Geometry of Vector Difference
Now that we know the angle between the vectors, we need to find the magnitude of their difference, ∣A−B∣. Geometrically, if we place A and B tail-to-tail, A−B is the vector pointing from the tip of B to the tip of A.
Alternatively, we can think of it as adding A and −B. Using the law of cosines for vector addition, the magnitude of the difference is given by:
∣A−B∣=A2+B2−2ABcosθ
Final Calculation
We simply substitute our known angle of 45∘ into the formula:
∣A−B∣=A2+B2−2ABcos(45∘)
Since cos(45∘)=21, we have:
∣A−B∣=A2+B2−2AB(21)
Simplifying the fraction 22 gives us 2. Thus, our final expression is:
∣A−B∣=A2+B2−2AB
This elegant result perfectly captures the geometric relationship between the two vectors.