Animated Solution for Mathematics - Differentiation: If 5f(x)+4f(x1)=x2−2,∀x=0 and y=9x2f(x), then y is strictly increasing in :
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Visualized Solution
Analyze the Functional Equation
Given functional equation: 5f(x)+4f(x1)=x2−2
Goal: Isolate f(x) to find the function y=9x2f(x).
Substitute x→x1
Substitute x→x1 in the original equation.
This creates a system of two equations.
Generate the Second Equation
New equation: 5f(x1)+4f(x)=(x1)2−2
Rearranged: 4f(x)+5f(x1)=x21−2…(2)
Eliminate f(x1)
Multiply Eq (1) by 5: 25f(x)+20f(x1)=5x2−10
Multiply Eq (2) by 4: 16f(x)+20f(x1)=x24−8
Solve for f(x)
Subtract the two equations to eliminate f(x1):
(25−16)f(x)=(5x2−10)−(x24−8)
9f(x)=5x2−x24−2
Define the Function y
Given: y=9x2f(x)
Substitute 9f(x): y=x2⋅(5x2−x24−2)
Result: y=5x4−2x2−4
Condition for Strictly Increasing
For a function to be strictly increasing, its derivative must be positive.
Condition: dxdy>0
Differentiate y
Differentiate y=5x4−2x2−4 with respect to x:
dxdy=20x3−4x
Factorize the Derivative
Factorize the derivative: 20x3−4x>0
4x(5x2−1)>0
4x(5x−1)(5x+1)>0
Find Critical Points
Equate factors to zero to find critical points.
Critical points: x=0,x=51,x=−51
The Wavy Curve Method
Plot the critical points on a number line.
Draw the wavy curve starting with a positive sign from the rightmost interval.
Identify the Signs
Sign scheme:
(+) for x>51 and −51<x<0
(−) for 0<x<51 and x<−51
Select the Increasing Intervals
We need dxdy>0, so select the positive intervals.
x∈(−51,0)∪(51,∞)
Final Conclusion
The strictly increasing intervals match Option (2).
Final Answer: (−51,0)∪(51,∞)
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The Sigma Insight: Monotonicity
Solution Diagram
Analyzing the Setup
The functional equation provided is:
5f(x)+4f(x1)=x2−2
To solve for f(x), we recognize the symmetry between x and x1. By replacing x with x1 in the original equation, we generate a second equation:
4f(x)+5f(x1)=x21−2
The Master Equation
We now have a system of two linear equations with two variables, f(x) and f(x1). To isolate f(x), we multiply the first equation by 5 and the second equation by 4:
25f(x)+20f(x1)=5x2−10
16f(x)+20f(x1)=x24−8
Subtracting the second resulting equation from the first yields:
9f(x)=5x2−x24−2
f(x)=91(5x2−x24−2)
Substituting this into the expression y=9x2f(x), we obtain:
y=5x4−2x2−4
The Calculus Transition
To determine where the function y is strictly increasing, we must satisfy the condition dxdy>0. Differentiating the polynomial y=5x4−2x2−4 with respect to x gives:
dxdy=20x3−4x
We set this derivative to be strictly positive:
4x(5x2−1)>0
Factoring the expression further, we get:
4x(5x−1)(5x+1)>0
The Wavy Curve Method
We identify the critical points on the number line: x=0, x=51, and x=−51.
Applying the Wavy Curve method, we test the intervals. Starting from the rightmost interval (51,∞) with a positive sign and alternating signs across each critical point, we find the regions where the derivative is positive.
The function y is strictly increasing on the intervals: