Animated Solution for Mathematics - Trigonometry: If 5, 5r, 5r2 are the lengths of the sides of a triangle, then r cannot be equal to :
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Visualized Solution
Identify the Sides of the Triangle
Given sides: a=5, b=5r, c=5r2
Assume r>0 since lengths must be positive.
The Triangle Inequality Theorem
Triangle Inequality: Sum of any two sides > Third side
1. a+b>c
2. b+c>a
3. c+a>b
Setting up Inequality 1: a+b>c
First condition: a+b>c
Substitute values: 5+5r>5r2
Simplifying Inequality 1
Divide by 5: 1+r>r2
Rearrange: r2−r−1<0
Solving the First Quadratic Inequality
Roots of r2−r−1=0 are r=21±5
Since r>0, the valid range is 0<r<21+5
21+5≈1.618
Setting up Inequality 2: b+c>a
Second condition: b+c>a
Substitute values: 5r+5r2>5
Simplifying Inequality 2
Divide by 5: r+r2>1
Rearrange: r2+r−1>0
Solving the Second Quadratic Inequality
Roots of r2+r−1=0 are r=2−1±5
We need r2+r−1>0 and r>0
Valid range: r>25−1≈0.618
Analyzing the Third Inequality: c+a>b
Third condition: 5r2+5>5r
Divide by 5 and rearrange: r2−r+1>0
Discriminant D=(−1)2−4(1)(1)=−3<0
Always true for all real r.
Combining All Conditions
Intersection of all valid ranges:
25−1<r<25+1
Numerical Range: 0.618<r<1.618
Checking Options 1 and 2
Option 1: r=23=1.5 (Inside range)
Option 2: r=43=0.75 (Inside range)
Checking Option 3
Option 3: r=45=1.25 (Inside range)
Checking Option 4 (The Answer)
Option 4: r=47=1.75
1.75>1.618, so it is OUTSIDE the valid range.
Therefore, r cannot be 47.
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The Sigma Insight: Properties of Triangles
Solution Diagram
Analyzing the Setup
Imagine you are standing in a workshop, tasked with building a triangle using three wooden rods. You are given lengths of 5, 5r, and 5r2.
Geometry is a strict master. If you pick an r that is too large or too small, those rods will never meet at the corners. They will either be too short to bridge the gap or one will be so long that the other two cannot reach its ends.
We must master the art of the Triangle Inequality Theorem to find exactly which values of r are allowed.
The Three Pillars of Existence
For any three segments to form a triangle, they must satisfy the Triangle Inequality Theorem. This is the fundamental requirement for closure in Euclidean space.
We have three conditions to satisfy:
1. 5+5r>5r2
2. 5r+5r2>5
3. 5r2+5>5r
Let's simplify these. By dividing each by 5, we obtain:
1+r>r2
r+r2>1
r2+1>r
These are the gates we must pass through.
Solving the Quadratic Gates
Let's look at the first condition: r2−r−1<0. To solve this, we find the roots of the quadratic r2−r−1=0 using the quadratic formula:
r=21±5
Since we know r must be positive, we focus on the interval 0<r<21+5. This gives us an upper bound of approximately 1.618.
Next, consider the second condition: r2+r−1>0. We find the roots of r2+r−1=0, which are r=2−1±5.
Since we need the expression to be greater than zero, we take the positive root: r>25−1, which is approximately 0.618.
Finally, consider the third condition: r2−r+1>0. If you calculate the discriminant D=(−1)2−4(1)(1)=−3, you will see it is negative.
This means the parabola r2−r+1 never touches the x-axis. Since it opens upwards, it is always positive for any real r. This condition is satisfied for all values.
The Final Intersection
Now, we combine our findings. We need r to be greater than 0.618 AND less than 1.618.
Our valid range for r is:
25−1<r<25+1
Now, look at your options. We have 23=1.5, 43=0.75, and 45=1.25. All of these fall comfortably within our 'Golden' range.
However, consider 47=1.75. This value is clearly greater than 1.618.
If you tried to build a triangle with r=1.75, the side 5r2 would be so long that the other two sides, 5 and 5r, would simply fail to connect.
Conclusion
Mathematics is often about finding the boundaries of the possible. By applying the Triangle Inequality, we defined the physical limits of a geometric shape.
The value r=47 lies outside these limits, making it the only impossible choice. Keep this logic in your toolkit—whenever you see constraints, look for the inequalities that define them.