Sigma Percentile
JEE Main 2019
LEVELJEE Main

Animated Solution for Chemistry - d and f-Block Elements: The highest possible oxidation states of uranium and plutonium, respectively, are

Select Answer:

Visualized Solution

  • $

The Sigma Insight: Inner Transition Elements

Solution Diagram

The Actinoid Anomaly

When we study the f-block elements, the lanthanoids often seem quite well-behaved, stubbornly sticking to their favorite oxidation state. But the actinoids? They are the rebels of the periodic table. They exhibit a fascinating and wide variety of oxidation states.
To understand why, we have to look at their energy levels. In the actinoid series, the , , and orbitals are remarkably close to each other in terms of energy.

The Energy Level Dance

Because the energy gap () between these subshells is so incredibly small, the electrons don't just stay confined to their specific orbitals when it comes to chemical bonding. Instead, electrons from all three subshells—, , and —can easily participate.
This unique property is the secret behind their ability to expand their oxidation states significantly. They can lose or share a large number of valence electrons, leading to highly oxidized compounds.

Uranium's Limit

Let us focus on Uranium (U), a famous early actinoid with an atomic number of . If we look at its electronic configuration, it is .
Uranium has the ability to lose all six of these valence electrons. By doing so, it achieves a maximum oxidation state of . A classic, real-world example of this is Uranium hexafluoride (), a compound heavily used in the uranium enrichment process.

Plutonium's Peak

Moving a bit further down the series, we encounter Plutonium (Pu), with an atomic number of . Its electronic configuration is .
Plutonium pushes the boundaries even further. It can utilize up to seven of its valence electrons for bonding, reaching an impressive maximum oxidation state of ! While these compounds are rare and highly oxidizing, they do exist under specific conditions.

The Final Verdict

Bringing it all together, the highest possible oxidation states for Uranium and Plutonium are and , respectively.
As a bonus fact, it is crucial to remember the general trend among the early actinoids. The maximum oxidation state increases from Uranium () to Neptunium () and Plutonium (), and then it drops back down for Americium (). This specific trend is a favorite concept for examiners, so keep it locked in your memory!

Similar Questions

LEVELJEE Main

Most common oxidation states of Ce (Cerium) are

(A)
+ 3, + 4
(B)
+ 2, + 3
(C)
+ 2, + 1
(D)
+ 3, + 5
JEE Main 2021
LEVELJEE Main

The ion is a strong reducing agent in spite of its ground state electronic configuration (outermost) : [Atomic number of Eu = 63]

(A)
(B)
(C)
(D)
LEVELJEE Main

Larger number of oxidation states are exhibited by the actinoides than those by the lanthanoides, the main reason being

(A)
4f orbitals more diffused than the 5f orbitals
(B)
lesser energy difference between 5f and 6d than between 4f and 5d orbitals
(C)
more energy difference between 5f and 6d than between 4f and 5d orbitals
(D)
more reactive nature of the actinoides than the lanthanoides
JEE Main 2020
LEVELJEE Main

The electronic configuration of bivalent europium and trivalent cerium are (atomic number : )

(A)
and
(B)
and
(C)
and
(D)
and
LEVELJEE Main

The actinoids exhibit more number of oxidation states in general than the lanthanoids. This is because

(A)
the 5f orbitals are more buried than the 4f orbitals
(B)
there is a similarity between 4f and 5f orbitals in their angular part of the wave function
(C)
the actinoids are more reactive than the lanthanoids
(D)
the 5f orbitals extend farther from the nucleus than the 4f orbitals
LEVELJEE Main

Cerium () is an important member of the lanthanides. Which of the following statements about cerium is incorrect?

(A)
The common oxidation states of cerium are and
(B)
The oxidation state of cerium is more stable than the oxidation state
(C)
The oxidation state of cerium is not known in solutions
(D)
Cerium (IV) acts as an oxidising agent
JEE Main 2020
LEVELJEE Main

The elements with atomic numbers 101 and 104 belong to, respectively,

(A)
actinoids and group 4
(B)
actinoids and group 6
(C)
group 6 and actinoids
(D)
group 11 and group 4
LEVELJEE Main

In context of the lanthanoids, which of the following statements is not correct?

(A)
There is a gradual decrease in the radii of the members with increasing atomic number in the series.
(B)
All the member exhibit oxidation state.
(C)
Because of similar properties the separation of lanthanoids is not easy.
(D)
Availability of electrons results in the formation of compounds in state for all the members of the series.
JEE Main 2019
LEVELJEE Main

The correct order of atomic radii is

(A)
Ho > N > Eu > Ce
(B)
N > Ce > Eu > Ho
(C)
Eu > Ce > Ho > N
(D)
Ce > Eu > Ho > N
JEE Main 2021
LEVELJEE Main

The number of electrons in the ground state electronic configuration of is ...... . [Atomic number of Gd is 64.]