Sigma Percentile
JEE Advanced 2019
LEVELJEE Main

Animated Solution for Chemistry - Salt Analysis: The green colour produced in the borax bead test of a chromium(III) salt is due to –

Select Answer:

Visualized Solution

Borax Bead Test

  • The borax bead test is used to identify certain transition metals.
  • A borax bead is heated with the salt in a flame.

Formation of Boric Anhydride

  • Borax () on heating loses water and decomposes into sodium metaborate and boric anhydride.

Decomposition of Chromium Salt

  • The chromium(III) salt decomposes on heating to form chromium(III) oxide.

Formation of the Coloured Bead

  • The chromium(III) oxide reacts with boric anhydride to form chromium(III) metaborate, which is green in colour.

Final Answer

  • The green colour is due to .

The Way Forward

  • Different metals give different characteristic colours.
  • For example, Cobalt gives a blue bead ().

The Sigma Insight: Salt Analysis

Solution Diagram

The Magic of the Borax Bead Test

Imagine you are in a chemistry lab, holding a thin platinum wire with a small loop at the end. You dip this loop into some white borax powder and hold it in the hot flame of a Bunsen burner. The powder sizzles, loses its water, and melts into a beautiful, transparent, glassy bead. This is the famous borax bead test, a classic and elegant method used to identify certain transition metals.
But what exactly is this glassy bead made of? When borax, which is sodium tetraborate decahydrate (), is heated, it first loses its water of crystallization. Upon further heating, it decomposes into sodium metaborate () and boric anhydride ().
This boric anhydride is the crucial ingredient. It acts as a flux, ready to react with metal oxides to form brightly colored compounds.

The Chromium Reaction

Now, let's introduce our mystery guest: a chromium(III) salt. When you touch the hot, transparent bead to a tiny speck of the chromium salt and put it back into the flame, a chemical transformation occurs.
First, the heat of the flame decomposes the chromium(III) salt into chromium(III) oxide ().
Next comes the magic. The newly formed chromium(III) oxide reacts with the boric anhydride present in the glassy bead. They combine to form a new compound called chromium(III) metaborate.

The Final Color

It is this specific compound, chromium(III) metaborate (), that imparts a characteristic, vibrant green color to the bead.
This test is incredibly reliable for transition metals because their metaborates have distinct, signature colors. For instance, cobalt forms a deep blue bead, while copper can form a blue or green bead depending on whether you use an oxidizing or reducing flame. Understanding these reactions not only helps you ace your exams but also gives you a glimpse into the beautiful, colorful world of inorganic chemistry!

Similar Questions

JEE Advanced 2023
LEVELJEE Advanced

In the scheme given below, X and Y, respectively, are

(A)
and
(B)
and
(C)
and
(D)
and
JEE Advanced 2021
LEVELJEE Advanced

Comprehension Passage

The reaction of with freshly prepared solution produces a dark blue precipitate called Turnbull's blue. Reaction of with the solution in complete absence of air produces a white precipitate , which turns blue in air. Mixing the solution with , followed by a slow addition of concentrated through the side of the test tube produces a brown ring.
Question 1:

Precipitate is

(A)
(B)
(C)
(D)
Question 2:

Among the following, the brown ring is due to the formation of

(A)
(B)
(C)
(D)
JEE Advanced 2022
LEVELJEE Main

The reaction and in water produces a precipitate that dissolves upon the addition of of appropriate concentration. The dissolution of the precipitate is due to the formation of

(A)
(B)
(C)
(D)
JEE Advanced 2018
LEVELJEE Advanced

The correct option(s) to distinguish nitrate salts of and taken separately is (are) :-

* Multiple Correct Options
(A)
shows the characteristic green colour in the flame test
(B)
Only shows the formation of precipitate by passing in acidic medium
(C)
Only shows the formation of precipitate by passing in faintly basic medium
(D)
has higher reduction potential than (measured under similar conditions)
JEE Main 2025
LEVELJEE Main

During sodium nitroprusside test of sulphide ion in an aqueous solution, one of the ligands coordinated to the metal ion is converted to

(A)
NOS^{-}
(B)
SCN^{-}
(C)
SNO^{-}
(D)
NCS^{-}
JEE Advanced 2016
LEVELJEE Main

In the following reaction sequence in aqueous soluiton, the species X, Y and Z respectively, are –

(A)
, ,
(B)
, ,
(C)
, ,
(D)
, ,
JEE Advanced 2021
LEVELJEE Advanced

A mixture of two salts is used to prepare a solution , which gives the following results : White precipitate(s) only (aq. solution of the salts) White precipitate(s) only The correct option(s) for the salt mixture is(are)

* Multiple Correct Options
(A)
and
(B)
and
(C)
and
(D)
and
JEE Advanced 2025
LEVELJEE Main

The correct match of the group reagents in List-I for precipitating the metal ion given in List-II from solutions, is

List-I

(P)
Passing in the presence of
(Q)
in the presence of
(R)
in the presence of
(S)
Passing in the presence of dilute

List-II

(1)
(2)
(3)
(4)
(5)
JEE Advanced 2020
LEVELJEE Main

A colorless aqueous solution contains nitrates of two metals, and . When it was added to an aqueous solution of , a white precipitate was formed. This precipitate was found to be partly soluble in hot water to give a residue and a solution . The residue was soluble in aq. and also in excess sodium thiosulfate. The hot solution gave a yellow precipitate with . The metals and , respectively, are

(A)
and
(B)
and
(C)
and
(D)
and
JEE Advanced 2016
LEVELJEE Advanced

The reagent(s) that can selectively precipiate from a mixture of and in aqueous soltuion is(are) :

* Multiple Correct Options
(A)
(B)
(C)
(D)