The Magic of Combustion Analysis
Imagine you have a mystery gas, a hydrocarbon, and you want to know exactly what it's made of. You can't just look at it under a microscope and count the atoms. Instead, chemists use a brilliant technique called Combustion Analysis.
By burning the hydrocarbon completely in the presence of excess oxygen, we force a chemical transformation. Every single carbon atom in the original molecule is converted into carbon dioxide (CO2), and every single hydrogen atom is converted into water (H2O). This means the mass of carbon in the CO2 produced is exactly equal to the mass of carbon in the original sample. The same logic applies to the hydrogen in the water.
Tracking Down the Carbon
Let's start by analyzing the carbon dioxide. We are given that 3.08 g of CO2 is produced. We know from the periodic table that the molar mass of CO2 is 44 g/mol (since Carbon is 12 and two Oxygens are 32). Out of these 44 g, exactly 12 g come from carbon.
Using a simple unitary method, we can find the mass of carbon in our specific sample:
Mass of Carbon=4412×3.08 g
Calculating this gives us exactly 0.84 g of Carbon.
Tracking Down the Hydrogen
Next, we turn our attention to the water produced, which is 0.72 g. The molar mass of H2O is 18 g/mol (two Hydrogens are 2, and one Oxygen is 16). Out of these 18 g, exactly 2 g come from hydrogen.
Again, applying the unitary method:
Mass of Hydrogen=182×0.72 g
This calculation yields exactly 0.08 g of Hydrogen.
Finding the Simplest Ratio
Now that we have the masses of both elements, we need to find their molar ratio to determine the empirical formula. The empirical formula represents the simplest whole-number ratio of atoms in a compound.
We convert the masses into moles by dividing by their respective atomic masses:
Moles of C=120.84=0.07 mol
Moles of H=10.08=0.08 mol
Notice how clean these numbers are? That is always a great sign in chemistry problems! The molar ratio of Carbon to Hydrogen is 0.07:0.08.
To convert this into a whole-number ratio, we simply multiply both sides by 100, giving us 7:8.
Therefore, the simplest formula that fits this ratio is C7H8. This is our empirical formula, and it perfectly matches option (d).