Analyzing the Setup
Imagine four distinct particles situated at the corners of a square. We are given their masses as mA=m, mB=2m, mC=3m, and mD=4m.
Each particle is experiencing an acceleration of the exact same magnitude, a, but they are all moving in completely different directions. To make sense of this chaotic motion, we must anchor our perspective using a coordinate system. Let's assign vector notation to each particle's acceleration based on the standard X-Y axes:
Particle A is accelerating to the left: aA=−ai^
Particle B is accelerating upwards: aB=aj^
Particle C is accelerating to the right: aC=ai^
Particle D is accelerating downwards: aD=−aj^
The Master Equation
When dealing with a system of discrete particles, the acceleration of the centre of mass (aCM) is simply the mass-weighted average of the individual accelerations. The master formula is:
aCM=mA+mB+mC+mDmAaA+mBaB+mCaC+mDaD
Vector Substitution and Simplification
Now, we carefully substitute our known masses and their corresponding acceleration vectors into the formula.
aCM=m+2m+3m+4mm(−ai^)+2m(aj^)+3m(ai^)+4m(−aj^)
The denominator is simply the total mass of the system, which adds up to 10m. For the numerator, we expand the terms:
aCM=10m−mai^+2maj^+3mai^−4maj^
To simplify, we group the i^ components together and the j^ components together.
For the i^ direction: 3mai^−mai^=2mai^
For the j^ direction: 2maj^−4maj^=−2maj^
The Final Result
Putting it all back together, we get:
By factoring out 2ma and canceling the mass m, we arrive at our final elegant expression:
This result tells us a beautiful physical truth: despite the individual particles pulling in all four cardinal directions, the heavy mass of particle D (4m) pulling down and particle C (3m) pulling right dominates the system, causing the centre of mass to accelerate diagonally into the fourth quadrant.