Sigma Percentile
JEE Main 2002
LEVELJEE Main

Animated Solution for Chemistry - Electrochemistry: For the following cell with hydrogen electrodes at two different pressures and emf is given by

Select Answer:

Visualized Solution

  • Anode (LHS): Oxidation
  • Cathode (RHS): Reduction

  • Anode:
  • Cathode:

  • Number of electrons transferred,
  • Reaction Quotient,
  • Standard Cell Potential,

  • Condition for Spontaneity:

The Sigma Insight: Electrochemical Cells

Solution Diagram

Analyzing the Setup

Imagine you are looking at a fascinating electrochemical setup known as a gas concentration cell. In this specific problem, we have two identical hydrogen electrodes, but there is a twist—they are operating at different pressures, and .
The cell representation is given as:
By convention, the left side of the cell representation is always the anode, where oxidation takes place. The right side is the cathode, where reduction occurs. Because both electrodes are made of the exact same chemical species (hydrogen), the standard cell potential is exactly zero. The only driving force for this cell is the difference in pressure!

The Master Equation

Let's break down the chemistry happening at each electrode.
At the anode, hydrogen gas loses electrons:
At the cathode, hydrogen ions gain electrons:
When we add these two half-reactions together, the ions and the electrons perfectly cancel out. The overall net reaction is beautifully simple:
From this balanced equation, we can extract two critical pieces of information for the Nernst equation. First, the number of electrons transferred is . Second, the reaction quotient is the ratio of the product pressure to the reactant pressure, which gives us .

Final Calculation

Now, we bring in the heavy artillery—the Nernst equation:
Substituting our known values into the equation:
To clean up the expression and remove the negative sign, we simply take the reciprocal of the fraction inside the logarithm. This is a standard mathematical trick that makes the final answer look much more elegant:
And there we have it! The cell potential is directly proportional to the natural logarithm of the pressure ratio. For the cell to be spontaneous (), the initial pressure must be greater than the final pressure . It perfectly aligns with our physical intuition: gas naturally wants to expand from a region of high pressure to a region of low pressure!

Similar Questions

JEE Main 2020
LEVELJEE Advanced

What would be the electrode potential for the given half-cell reaction at ? …… . ; (; Temp ; oxygen under std. atm. pressure of )

LEVELJEE Main

The reduction potential of hydrogen half-cell will be negative if

(A)
and
(B)
and
(C)
and
(D)
and
JEE Advanced 2018
LEVELJEE Main

For the electrochemical cell, the standard emf of the cell is at . When the concentration of is changed to , the cell potential changes to at . The value of is______. (given, , where is the Faraday constant and is the gas constant, )

JEE Main 2021
LEVELJEE Advanced

For the cell the cell potential, For the cell, the cell potential . (Round off the nearest integer).

LEVELJEE Main

The standard emf of a cell, involving one electron change is found to be at . The equilibrium constant of the reaction is ()

(A)
(B)
(C)
(D)
LEVELJEE Main

For the redox reaction taking place in a cell, is . for the cell will be

(A)
2.14 V
(B)
1.80 V
(C)
1.07 V
(D)
0.82 V
JEE Main 2021
LEVELJEE Main

For the galvanic cell, , . (Nearest integer) [Use , , ]

LEVELJEE Main

For a cell given below cell is

(A)
(B)
(C)
(D)
LEVELJEE Main

For a cell reaction involving a two electron change, the standard emf of the cell is found to be at . The equilibrium constant of the reaction at will be

(A)
(B)
(C)
(D)
JEE Main 2021
LEVELJEE Main

Emf of the following cell at in is , The value of is ......... . (Rounded off to the nearest integer). [Given, , , ]