Analyzing the Setup
Imagine you are conducting the classic photoelectric effect experiment. You shine light of various frequencies onto a metal surface and measure the stopping potential required to halt the fastest ejected electrons. The graph provided in the problem is a direct visual representation of this experiment, plotting stopping potential VStop against the incident frequency f.
The question asks for the minimum energy required to eject an electron. In the language of physics, this minimum energy is known as the work function (ϕ0) of the metal.
The Master Equation
According to Einstein's photoelectric equation, the maximum kinetic energy of ejected electrons is given by:
eVStop=hf−ϕ0
At the threshold frequency (
f0), the incident photons have just enough energy to overcome the work function, meaning the ejected electrons have zero kinetic energy. Consequently, the stopping potential
VStop is exactly zero.
0=hf0−ϕ0⟹ϕ0=hf0
Looking closely at the graph, the line intersects the x-axis at point B. The coordinates of point B are (5.5,0). This x-intercept is our golden ticket—it tells us that the threshold frequency f0 is exactly 5.5×1014 Hz.
Final Calculation
Now, we simply substitute this value into our work function equation along with Planck's constant (
h=6.62×10−34 J⋅s):
ϕ0=(6.62×10−34)×(5.5×1014)
ϕ0=36.41×10−20 J
I know this number looks a bit messy, but let's take a breath. The options provided are in electron-volts (eV), not Joules. To convert our energy into eV, we must divide by the elementary charge (
e=1.6×10−19 C):
ϕ0=1.6×10−1936.41×10−20 eV
To make the division easier, let's adjust the decimal point in the numerator:
ϕ0=1.6×10−193.641×10−19 eV=1.63.641 eV
Calculating this gives us approximately 2.27 eV. This perfectly matches option (c). The beauty of this problem lies in how a simple geometric feature—the x-intercept—directly unlocks the quantum properties of the metal!