Sigma Percentile
JEE Main 2020
LEVELJEE Main

Animated Solution for Physics - Dual Nature of Matter and Radiation: The following figure shows few data points in a photoelectric effect experiment for a certain metal. The minimum energy for ejection of electron from its surface is (Take, Planck's constant, J-s)

Select Answer:

Visualized Solution

  • Graph of vs

  • Minimum energy for ejection = Work Function ()

  • At threshold frequency , .
  • From graph, point B is .

  • Key Takeaway: x-intercept
  • What if the x-axis was ?

The Sigma Insight: Photoelectric Effect

Solution Diagram

Analyzing the Setup

Imagine you are conducting the classic photoelectric effect experiment. You shine light of various frequencies onto a metal surface and measure the stopping potential required to halt the fastest ejected electrons. The graph provided in the problem is a direct visual representation of this experiment, plotting stopping potential against the incident frequency .
The question asks for the minimum energy required to eject an electron. In the language of physics, this minimum energy is known as the work function () of the metal.

The Master Equation

According to Einstein's photoelectric equation, the maximum kinetic energy of ejected electrons is given by:
At the threshold frequency (), the incident photons have just enough energy to overcome the work function, meaning the ejected electrons have zero kinetic energy. Consequently, the stopping potential is exactly zero.
Looking closely at the graph, the line intersects the x-axis at point B. The coordinates of point B are . This x-intercept is our golden ticket—it tells us that the threshold frequency is exactly .

Final Calculation

Now, we simply substitute this value into our work function equation along with Planck's constant ():
I know this number looks a bit messy, but let's take a breath. The options provided are in electron-volts (eV), not Joules. To convert our energy into eV, we must divide by the elementary charge ():
To make the division easier, let's adjust the decimal point in the numerator:
Calculating this gives us approximately . This perfectly matches option (c). The beauty of this problem lies in how a simple geometric feature—the x-intercept—directly unlocks the quantum properties of the metal!

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