The phenomenon of self-induction is one of the most fascinating aspects of electromagnetism. It is nature's way of maintaining the status quo in an electrical circuit. In this problem, we explore the inner workings of a fluorescent lamp choke, which is essentially a tightly wound coil of wire—an inductor.
Analyzing the Setup
Imagine the current flowing through the choke. Suddenly, this current is forced to drop from 0.25 A to zero in a mere 0.025 ms. According to Lenz's Law, the inductor despises this sudden change. It fights back by generating a "reverse voltage" to keep the current flowing.
This induced electromotive force (emf) is given as 100 V. Our mission is to determine the self-inductance, L, of this choke, which measures its "electrical inertia."
The Master Equation
The mathematical engine driving this phenomenon is Faraday's Law of Induction applied to a single coil. The magnitude of the induced emf is directly proportional to the rate of change of current:
E=LΔtΔI
We can rearrange this equation to isolate our target variable, the self-inductance
L:
L=ΔIE⋅Δt
The Crucial Unit Conversion
Before we rush into substituting the numbers, we must pause and inspect our units. Physics is unforgiving when it comes to mismatched units!
The time duration is given as
Δt=0.025 ms. To use standard SI units, we must convert this to seconds:
Δt=0.025×10−3 s
The change in current is straightforward:
ΔI=0.25 A−0 A=0.25 A
Final Calculation
Now, we substitute our pristine, unit-corrected values into the rearranged formula:
L=0.25100×(0.025×10−3)
Let's simplify the numerator first. Multiplying
100 by
0.025 gives us
2.5:
L=0.252.5×10−3
Dividing
2.5 by
0.25 yields exactly
10:
L=10×10−3 H
The question specifically asks for the answer in millihenrys (mH). Since 1 mH=10−3 H, we can seamlessly write our final answer:
L=10 mH
This elegant result shows how a relatively small inductance can produce a massive 100 V spike if the current is interrupted rapidly enough!