Sigma Percentile
JEE Main 2020
LEVELJEE Main

Animated Solution for Physics - Electromagnetic Induction: In a fluorescent lamp choke (a small transformer) 100 V of reverse voltage is produced when the choke current changes uniformly from 0.25A to 0 in a duration of 0.025 ms. The self-inductance of the choke (in mH) is estimated to be …… .

Enter Numerical Value:

Visualized Solution

The Sigma Insight: Self and Mutual Inductance

Solution Diagram
The phenomenon of self-induction is one of the most fascinating aspects of electromagnetism. It is nature's way of maintaining the status quo in an electrical circuit. In this problem, we explore the inner workings of a fluorescent lamp choke, which is essentially a tightly wound coil of wire—an inductor.

Analyzing the Setup

Imagine the current flowing through the choke. Suddenly, this current is forced to drop from to zero in a mere . According to Lenz's Law, the inductor despises this sudden change. It fights back by generating a "reverse voltage" to keep the current flowing.
This induced electromotive force (emf) is given as . Our mission is to determine the self-inductance, , of this choke, which measures its "electrical inertia."

The Master Equation

The mathematical engine driving this phenomenon is Faraday's Law of Induction applied to a single coil. The magnitude of the induced emf is directly proportional to the rate of change of current:
We can rearrange this equation to isolate our target variable, the self-inductance :

The Crucial Unit Conversion

Before we rush into substituting the numbers, we must pause and inspect our units. Physics is unforgiving when it comes to mismatched units!
The time duration is given as . To use standard SI units, we must convert this to seconds:
The change in current is straightforward:

Final Calculation

Now, we substitute our pristine, unit-corrected values into the rearranged formula:
Let's simplify the numerator first. Multiplying by gives us :
Dividing by yields exactly :
The question specifically asks for the answer in millihenrys (). Since , we can seamlessly write our final answer:
This elegant result shows how a relatively small inductance can produce a massive spike if the current is interrupted rapidly enough!

Similar Questions

JEE Main 2019
LEVELJEE Main

The self-induced emf of a coil is 25 V. When the current in it is changed at uniform rate from 10 A to 25 A in 1s, the change in the energy of the inductance is

(A)
437.5 J
(B)
740 J
(C)
637.5 J
(D)
540 J
LEVELJEE Main

When the current changes from to in , an emf of is induced in a coil. The coefficient of self-induction of the coil is

(A)
(B)
(C)
(D)
LEVELJEE Main

A coil of inductance and resistance is connected to a source of voltage . The current reaches half of its steady state value in

(A)
(B)
(C)
(D)
JEE Main 2019
LEVELJEE Main

A coil of self inductance and resistance is connected through a switch to a battery of internal resistance . After the switch is closed, the time taken for the current to attain of the saturation value is [Take, ]

(A)
(B)
(C)
(D)
JEE Advanced 2026
LEVELJEE Advanced

Consider a circuit consisting of a capacitor of capacitance and a coil with turns per unit length, cross sectional area and length , where . There is another coil of length , cross sectional area and turns per unit length completely inside the larger coil, as shown in the figure. The ends of this smaller coil are connected with each other by an insulated conducting wire. The self-inductance of the larger coil is . Neglecting edge effects and all the Ohmic resistances, the resonant frequency of the circuit is:

(A)
(B)
(C)
(D)
LEVELJEE Main

An inductor (), a resistor () and a battery () are initially connected in series as shown in the figure. After a long time, the battery is disconnected after short circuiting the points and . The current in the circuit after the short circuit is

(A)
(B)
(C)
(D)
LEVELJEE Main

A coil of inductance and resistance is connected to a battery. The current in the coil is at approximately the time

(A)
(B)
(C)
(D)
JEE Main 2021
LEVELJEE Main

An inductor of is connected to a battery through a resistor of and a switch. After a long time, when maximum current is set up in the circuit, the current is switched off. The current in the circuit after is . Then, is equal to ...... (Take, )

JEE Main 2021
LEVELJEE Main

An inductor coil stores 64 J of magnetic field energy and dissipates energy at the rate of 640 W when a current of 8A is passed through it. If this coil is joined across an ideal battery, find the time constant of the circuit in seconds.

(A)
0.4
(B)
0.8
(C)
0.125
(D)
0.2
JEE Main 2021
LEVELJEE Main

A coil of inductance having negligible resistance is connected to a source of supply whose voltage is given by (where, is in second). If the voltage is applied when , then the energy stored in the coil after is ............ J.