Sigma Percentile
JEE Advanced 1992
LEVELJEE Advanced

Animated Solution for Mathematics - Indefinite Integration: Find the indefinite integral

Visualized Solution

Splitting the Integral

  • Let

Substitution Strategy for

  • For , identify the fractional powers of : and
  • To eliminate fractions, find the LCM of denominators:
  • Substitute

Simplifying

  • Substitute into :
  • Factor out from the denominator:
  • Simplify the expression:

Polynomial Division

  • The degree of numerator () is greater than denominator ().
  • Perform polynomial division for

Integrating

  • Integrate term by term:
  • Substitute back into the expression.

Substitution Strategy for

  • For , identify powers:
  • Find the LCM of denominators:
  • Substitute

Simplifying with

  • The term in the denominator is troublesome.
  • Substitute and

Expanding the Term

  • Expand the numerator:
  • Divide each term by :
  • The integral becomes:

Integration by Parts

  • Split the integral:
  • For the first integral, use Integration by Parts: Let and
  • First integral becomes:

Finalizing

  • Evaluate the remaining integral from parts:
  • For the second integral, use substitution:
  • Combine everything for :

The Final Result

  • Combine the results:
  • Substitute back into the expression.
  • Add the constant of integration .
  • Key Takeaway: Use the LCM of fractional powers for radical substitutions to simplify complex integrals.

The Sigma Insight: Integration by Substitution

Analyzing the Setup

To solve the integral
we decompose the expression into two manageable parts: and . By addressing these separately, we simplify the complexity of the fractional exponents.

Solving the First Integral ()

We define . The least common multiple of the denominators and is .
We apply the substitution , which implies . Substituting these into the integral yields:
Performing polynomial long division on , we obtain the alternating series:
Integrating term by term and substituting back, we find:

Solving the Second Integral ()

We define . The LCM of the denominators and is .
We substitute , which gives . This transforms the integral into:
To simplify further, we use the substitution , implying and :

Final Calculation

Expanding the integral, we have:
Using integration by parts for the first term and simple substitution for the second, we get:
Substituting back into the expression, the final result is the sum of and plus the constant of integration .

Similar Questions

JEE Main 2020 (9 January Shift 1)
LEVELJEE Main

Find integration

(A)
(B)
(C)
(D)
JEE Main 2024 (27 Jan Shift 2)
LEVELJEE Main

The integral equal to :

(A)
(B)
(C)
(D)
JEE Advanced 1985
LEVELJEE Advanced

Evaluate the following

JEE Advanced 2006
LEVELJEE Main

(A)
(B)
(C)
(D)
JEE Advanced 1984
LEVELJEE Main

Evaluate the following

JEE Main 2019 (12 April Shift 1)
LEVELJEE Main

The integral is equal to :

(A)
(B)
(C)
(D)
JEE Advanced 1996
LEVELJEE Main

Evaluate

JEE Advanced 1989
LEVELJEE Main

Evaluate

JEE Main 2016
LEVELJEE Main

The integral is equal to

(A)
(B)
(C)
(D)
JEE Main 2007
LEVELJEE Main

equals

(A)
(B)
(C)
(D)