Analyzing the Setup
Welcome, fellow traveler of the mathematical landscape. Today, we stand before an integral that, at first glance, seems designed to intimidate:
I=∫0πe∣cosx∣(2sin(21cosx)+3cos(21cosx))sinxdx
It contains exponentials, absolute values, and nested trigonometric functions. But remember, in the world of JEE Advanced, complexity is often just a mask for elegance. Our job is to peel back that mask.
The Power of Substitution
Whenever you see a function and its derivative sitting together, your intuition should immediately fire. Look at the term sinxdx at the end of our integral; it is the derivative of cosx, which appears repeatedly inside the other functions.
Let t=cosx. Then, dt=−sinxdx, or sinxdx=−dt. This substitution is the key that unlocks the door.
When x=0, t=cos(0)=1. When x=π, t=cos(π)=−1. Our integral transforms into:
I=∫1−1e∣t∣(2sin(2t)+3cos(2t))(−dt)
The Beauty of Symmetry
Now, let us clean up. That negative sign from −dt is a gift; we can use it to flip the limits of integration from [1,−1] to [−1,1].
Now we have:
I=∫−11e∣t∣(2sin(2t)+3cos(2t))dt
Whenever you see limits from −a to a, your brain should scream: "Check for even and odd functions!" This is a favorite JEE tactic.
Let us split the integral into two parts:
I1=∫−112e∣t∣sin(2t)dt,I2=∫−113e∣t∣cos(2t)dt
For I1, the function f1(t)=2e∣t∣sin(2t) is odd because f1(−t)=−f1(t). The integral of an odd function over symmetric limits is zero, as the positive and negative areas cancel out perfectly. We are left only with I2.
The Final Integration
Since f2(t)=3e∣t∣cos(2t) is an even function, we can simplify I2 to:
I2=2∫013etcos(2t)dt=6∫01etcos(2t)dt
We are now left with a standard integral. We use the standard formula:
∫eatcos(bt)dt=a2+b2eat(acos(bt)+bsin(bt))
Here, a=1 and b=1/2. The denominator a2+b2=1+1/4=5/4. The integral becomes:
6×54[et(cos(2t)+21sin(2t))]01
Evaluating at the limits, we get:
524[e1(cos(21)+21sin(21))−e0(cos(0)+0)]
This simplifies to our final, elegant answer:
524[ecos(21)+2esin(21)−1]
See? The complexity was just a test of your patience and your ability to spot the underlying symmetry. Keep practicing, and these patterns will become second nature!