The Case of the Missing Exponent
Solving the L-R Circuit Mystery
Imagine you are standing in front of a simple electrical circuit. You have a 20 V battery, a 5Ω resistor, and a 10 mH inductor, all connected in series. The moment you close the switch, you might expect the current to instantly jump to its maximum value. But the inductor acts like a stubborn bouncer, opposing any sudden change in the flow of electrons.
Because of this opposition, the current doesn't spike instantly; instead, it grows gradually, following a beautiful exponential curve. Let's dive into the mathematics of this growth and uncover a fascinating anomaly hidden within this specific JEE problem.
The Master Equation
The instantaneous current I(t) during the growth phase in an L-R circuit is governed by the standard equation:
Here, I0 represents the maximum, steady-state current that will flow through the circuit after an infinite amount of time (t=∞). At this point, the inductor stops opposing the steady current, and the circuit behaves as if only the resistor is present. Therefore, I(∞)=I0=RE.
The Raw Calculation
The question asks for the ratio of the current at t=∞ to the current at t=40 s. Let's set up our ratio:
Ratio=I(40)I(∞)=I0(1−e−LR×40)I0=1−e−LR×401
Now, we need to carefully substitute our given values to evaluate the exponent term LRt. We have R=5Ω and L=10 mH=10×10−3 H.
LRt=10×10−35×40=0.015×40=500×40=20,000
The Anomaly
We have arrived at a massive exponent of 20,000. Let's plug this back into our ratio equation:
Mathematically, e−20000 is an astronomically small number—so close to zero that it is practically indistinguishable from it. Therefore, the denominator becomes 1−0=1, making our exact ratio exactly 1.
However, if you look at the options provided—(a) 1.06, (b) 1.15, (c) 1.46, (d) 0.84—the number 1 is nowhere to be found! In a high-pressure exam scenario, the standard strategy is to choose the nearest available option, which in this case is 1.06.
The Detective Work
Why would a JEE question have such a glaring mismatch? The secret lies in the hint provided at the end of the question: Take e2=7.389.
Why would the examiner give you the value of e2 if your exponent was going to be 20,000? They wouldn't. This is a massive clue that the intended exponent was actually 2.
If the exponent were 2, the ratio would be:
Ratio=1−e−21=1−7.38911=6.3897.389≈1.15
This perfectly matches option (b)! For the exponent to be 2, the time t should have been 4 ms instead of 40 s. This reveals that the question contained a typographical error. While the mathematically rigorous answer to the text as written leads us to approximate to 1.06, understanding the setter's intent shows the beauty of reverse-engineering a physics problem.