Sigma Percentile
LEVELJEE Main

Animated Solution for Physics - Laws of Motion: During paddling of a bicycle, the force of friction exerted by the ground on the two wheels is such that it acts (1990)

Select Answer:

Visualized Solution

  • A bicycle consists of two wheels connected by a rigid frame.
  • To understand friction, we must analyze each wheel independently.

  • The Rear Wheel is connected to the pedals via a chain. It is the driven wheel.
  • The Front Wheel is not connected to the drivetrain. It is an undriven wheel.

  • When a rider pedals, the chain applies a clockwise torque to the rear wheel.
  • This torque attempts to rotate the wheel around its axle.

  • Due to the clockwise rotation, the point of contact with the ground tries to move backward.
  • This creates a backward slip tendency at the bottom of the tire.

  • Static friction opposes this relative slipping.
  • Therefore, friction acts in the forward direction on the rear wheel.
  • This forward friction is the external force that propels the bicycle forward.

  • The front wheel receives no torque from the pedals.
  • Instead, as the bicycle moves, the frame pushes the front axle forward with a force .

  • A forward push at the axle gives the entire wheel a tendency to slide forward.
  • Without friction, the wheel would translate forward without rolling.

  • To prevent forward sliding, static friction acts in the backward direction.
  • This backward force provides the necessary clockwise torque to make the front wheel roll.

  • Rear Wheel: Friction is forward.
  • Front Wheel: Friction is backward.
  • This matches option (a).

The Sigma Insight: Static and Kinetic Friction

Solution Diagram

The Deceptive Simplicity of a Bicycle

Imagine you are riding a bicycle. It might look like just two simple wheels connected by a metal frame, but from a physics perspective, these two wheels operate under completely different mechanical conditions. The classic JEE problem asks us to determine the direction of friction on both wheels while pedaling. To solve this, we must completely dissect the mechanics of rolling and the true nature of static friction.

The Rear Wheel

The Engine of Forward Motion
The first critical step is to understand the distinct roles of the two wheels. The rear wheel is the 'driven' wheel—it is mechanically coupled to your pedals via the chain. When you push down on the pedals, the chain pulls on the rear cassette. This action applies a powerful clockwise torque, , to the rear wheel, attempting to spin it.
Now, visualize the exact point where the rubber meets the road. Because the wheel is being forced to rotate clockwise by the engine (your legs), that bottom-most contact point has a strong tendency to scrape and slip backward against the ground. Imagine if you were pedaling hard on a muddy surface—the dirt would fly backward!
This is where friction steps in as the hero. A fundamental law of physics is that friction always opposes relative slipping between two surfaces in contact. Since the tire is trying to slip backward, the ground exerts a static frictional force, , in the exact opposite direction, which is forward!
Here is the beautiful catch: this forward friction is the actual external force that propels the entire bicycle forward. This is where many students make a critical mistake. People often memorize that "friction always opposes motion," but in the case of a driven wheel, friction is the very force creating the forward motion!

The Front Wheel

The Reluctant Follower
Now, let's shift our gaze to the front wheel. There is no chain here, and absolutely no pedaling torque. It is an 'undriven' wheel. So how does it move? As the rear wheel drives the bike forward, the rigid frame of the bicycle simply pushes the front wheel's axle in the forward direction with a force .
If the ground were made of perfectly smooth, frictionless ice, this forward push at the axle would just cause the entire wheel to slide forward without rotating at all. The contact point has a clear tendency to slip forward.
To prevent this forward sliding, the ground must "grab" the bottom of the tire. It applies a frictional force, , in the backward direction. This backward force not only arrests the sliding but also provides the essential clockwise torque required to make the front wheel roll smoothly. Without this backward friction, the front wheel wouldn't roll; it would just skid!

The Grand Conclusion

When we put it all together, we see a magnificent interplay of forces. When pedaling, the friction on the rear wheel acts in the forward direction to propel the bike, while the friction on the front wheel acts in the backward direction to force it to roll. Therefore, the correct answer is that friction acts backward on the front wheel and forward on the rear wheel, matching option (a).

Similar Questions

LEVELJEE Main

Assertion It is easier to pull a heavy object than to push it on a level ground. Reason The magnitude of frictional force depends on the nature of the two surfaces in contact.

(A)
If Assertion is true, Reason is true; Reason is the correct explanation for Assertion
(B)
If Assertion is true, Reason is true; Reason is not a correct explanation for Assertion
(C)
If Assertion is true; Reason is false
(D)
If Assertion is false; Reason is true
LEVELJEE Main

A block of mass is on an inclined plane of angle . The coefficient of friction between the block and the plane is and . The block is held stationary by applying a force parallel to the plane. The direction of force pointing up the plane is taken to be positive. As is varied from to , the frictional force versus graph will look like (2010)

(A)
(B)
(C)
(D)
LEVELJEE Main

A small block of mass of lies on a fixed inclined plane which makes an angle with the horizontal. A horizontal force of acts on the block through its centre of mass as shown in the figure. The block remains stationary if (Take )

* Multiple Correct Options
(A)
.
(B)
and a frictional force acts on the block towards
(C)
and a frictional force acts on the block towards
(D)
and a frictional force acts on the block towards
LEVELJEE Main

The minimum force required to start pushing a body up a rough (frictional coefficient ) inclined plane is while the minimum force needed to prevent it from sliding down is . If the inclined plane makes an angle from the horizontal such that , then the ratio is

(A)
4
(B)
1
(C)
2
(D)
3
JEE Main 2015
LEVELJEE Main

Given in the figure are two blocks and of weight and respectively. These are being pressed against a wall by a force as shown in figure. If the coefficient of friction between the blocks is and between block and the wall is , the frictional force applied by the wall in block is

(A)
(B)
(C)
(D)
JEE Main 2021
LEVELJEE Advanced

When a body slides down from rest along a smooth inclined plane making an angle of with the horizontal, it takes time . When the same body slides down from the rest along a rough inclined plane making the same angle and through the same distance, it takes time , where is a constant greater than 1. The coefficient of friction between the body and the rough plane is , where is ......... .

LEVELJEE Main

In the figure, a ladder of mass is leaning against a wall. It is in static equilibrium making an angle with the horizontal floor. The coefficient of friction between the wall and the ladder is and that between the floor and the ladder is . The normal reaction of the wall on the ladder is and that of the floor is . If the ladder is about to slip, then (2014 Adv.)

* Multiple Correct Options
(A)
and
(B)
and
(C)
and
(D)
and
JEE Main 2021, 16 March Shift-I
LEVELJEE Main

A block of mass slides along a floor, while a force of magnitude is applied to it at an angle as shown in figure. The coefficient of kinetic friction is . Then, the block's acceleration is given by ( is acceleration due to gravity)

(A)
(B)
(C)
(D)
LEVELJEE Advanced

A block of mass and another mass are placed together (see figure) on an inclined plane with angle of inclination . Various values of are given in List I. The coefficient of friction between the block and the plane is always zero. The coefficient of static and dynamic friction between the block and the plane are equal to . In List II expressions for the friction on the block are given. Match the correct expression of the friction in List II with the angles given in List I, and choose the correct option. The acceleration due to gravity is denoted by . [Useful information ; ; ] \begin{tabular}{llll} \hline & List I & & List II \hline P. & & 1. & Q. & & 2. & R. & & 3. & S. & & 4. & \hline \end{tabular}

(A)
P-1, Q-1, R-1, S-3
(B)
P-2, Q-2, R-2, S-3
(C)
P-2, Q-2, R-2, S-4
(D)
P-2, Q-2, R-3, S-3
LEVELJEE Main

A block of mass is held against a wall applying a horizontal force of on the block. If the coefficient of friction between the block and the wall is , the magnitude of the frictional force acting on the block is

(A)
(B)
(C)
(D)