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The Sigma Insight: Bond Fission, Electronic Displacement and Hyperconjugation
The Restless Nature of Free Radicals
In the microscopic world of organic chemistry, stability is the ultimate goal. Atoms bond with each other to achieve a stable, noble-gas-like electron configuration, typically by pairing up their valence electrons. But what happens when a molecule is left with an odd number of electrons? Enter the free radical.
What is a Free Radical?
A free radical is a chemical species—an atom, molecule, or ion—that possesses at least one unpaired valence electron. Imagine a dance floor where everyone is paired up, but one person is left dancing alone. That lone dancer is the unpaired electron.
Take the methyl radical () as a classic example. It consists of a central carbon atom bonded to three hydrogen atoms. The carbon atom has four valence electrons; three are shared with the hydrogens, leaving one electron completely unpaired and alone.
Are They Charged?
A common misconception is to confuse free radicals with ions. It is crucial to understand that free radicals are electrically neutral.
Why? Because the total number of positively charged protons in the nuclei exactly balances the total number of negatively charged electrons in the species. They haven't gained an extra electron (which would make them an anion) nor have they lost an electron from a pair (which would make them a cation). They simply have a bond that broke evenly—a process known as homolytic cleavage—leaving one electron on each fragment.
The Drive for Stability
While they may be neutral, they are far from peaceful. Electrons have an intrinsic quantum mechanical preference to exist in pairs with opposite spins. An unpaired electron represents a high-energy, unstable state.
Because of this, free radicals are highly chemically reactive. They are on a relentless quest to find another electron to pair up with and complete their octet. They will aggressively attack other molecules, snatching atoms (often hydrogen) or adding themselves to double bonds just to satisfy that unpaired electron.
For instance, if two methyl radicals () encounter each other, they will instantly combine their unpaired electrons to form a stable covalent bond, creating an ethane molecule ().
Therefore, the defining characteristic of a free radical—its unpaired electron—is exactly what makes it so fiercely reactive.
Similar Questions
JEE Main 2006
LEVELJEE Main
The increasing order of stability of the following free radicals is
(A)
(B)
(C)
(D)
JEE Main 2013
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The order of stability of the following carbocations
(A)
III > II > I
(B)
II > III > I
(C)
I > II > III
(D)
III > I > II
JEE Main 2017
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Which of the following molecules is least resonance stabilised?
(A)
(B)
(C)
(D)
JEE Main 2021
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Among the given species the resonance stabilised carbocations are
(A)
(C) and (D) only
(B)
(A), (B) and (D) only
(C)
(A) and (B) only
(D)
(A), (B) and (C) only
JEE Main 2021
LEVELJEE Main
Choose the correct statement regarding the formation of carbocations A and B.
(A)
Carbocation B is more stable and formed relatively at faster rate.
(B)
Carbocation A is more stable and formed relatively at slow rate.
(C)
Carbocation B is more stable and formed relatively at slow rate.
(D)
Carbocation A is more stable and formed relatively at faster rate.
JEE Main 2020
LEVELJEE Advanced
The correct order of stability for the following alkoxides is
(A)
(C) > (B) > (A)
(B)
(B) > (C) > (A)
(C)
(B) > (A) > (C)
(D)
(C) > (A) > (B)
JEE Main 2020
LEVELJEE Main
Which one of the following compounds possesses the most acidic hydrogen?
(A)
(B)
(C)
(D)
LEVELJEE Advanced
Arrange the carbanions, , , , in order of their decreasing stability
(A)
(B)
(C)
(D)
JEE Main 2021
LEVELJEE Main
The correct order of acid character of the following compounds is
(A)
I > II > III > IV
(B)
III > II > I > IV
(C)
II > III > IV > I
(D)
IV > III > II > I
JEE Main 2021
LEVELJEE Main
The correct order of stability of given carbocation is
(A)
A > C > B > D
(B)
D > B > C > A
(C)
D > B > A > C
(D)
C > A > D > B
