Sigma Percentile
JEE Advanced 2014
LEVELJEE Advanced

Animated Solution for Chemistry - Organic Chemistry: Different possible thermal decomposition pathways for peroxyesters are shown below. Match each pathway from List-I with an appropriate structure from List-II.

List-I

(P)
Pathway P
(Q)
Pathway Q
(R)
Pathway R
(S)
Pathway S

List-II

(1)
(2)
(3)
(4)

Select Matching Pairs:

PMatches
QMatches
RMatches
SMatches

Visualized Solution

  • Peroxyesters decompose upon heating.
  • The bond is the weakest bond and undergoes homolytic cleavage first.

  • Concerted Pathway: If is highly stable (e.g., benzyl), the and bonds break simultaneously, releasing instantly.
  • Stepwise Pathway: If is unstable (e.g., phenyl), the bond breaks first to form , followed by the loss of .

  • (stable benzyl radical) Concerted loss of .
  • (methoxy radical) No further fragmentation.
  • Overall:
  • Matches Pathway P.

  • (unstable phenyl radical) Stepwise loss of .
  • No further fragmentation.
  • Overall:
  • Matches Pathway S.

  • Bulky alkoxy radicals can undergo -scission to form a stable carbonyl compound and a new radical .
  • The bond that breaks is the one that yields the most stable radical .

  • Concerted loss of .
  • -scission yields acetone and a stable benzyl radical ().
  • Matches Pathway Q.

  • Stepwise loss of .
  • -scission yields acetophenone and a methyl radical (), as methyl is more stable than phenyl.
  • Matches Pathway R.

The Sigma Insight: Types of Organic Reactions

Solution Diagram

The Anatomy of a Peroxyester

Welcome to a beautiful exploration of radical chemistry! When we subject peroxyesters to thermal stress, they don't just fall apart randomly. They follow precise, predictable pathways dictated by the stability of the intermediates they form. The journey always begins at the weakest link: the oxygen-oxygen single bond. Because this bond is exceptionally weak, it undergoes homolytic cleavage upon heating, initiating the decomposition process.

The Crossroads

Concerted vs. Stepwise
Once the bond is primed to break, the molecule faces a critical decision that depends entirely on the nature of the group attached to the carbonyl carbon.
Imagine this: if the group is capable of forming a highly stable radical—such as a resonance-stabilized benzyl radical ()—the molecule doesn't wait around. The carbon-carbon bond breaks at the exact same time as the oxygen-oxygen bond. This simultaneous rupture instantly releases carbon dioxide gas in what we call a concerted pathway.
However, if the group forms an unstable radical—like a phenyl radical (), where the unpaired electron is trapped in an unyielding orbital—the molecule is forced to take a slower, stepwise pathway. The bond breaks first to form a transient carboxylate radical (), which only later loses .

The Fate of the Alkoxy Radical: -Scission

While the left side of the molecule is busy losing , the right side forms an alkoxy radical (). If this radical is small and simple, like a methoxy radical (), it remains intact.
But there is a catch! If the alkoxy radical is bulky and highly branched, it can undergo a fascinating fragmentation known as -scission. It cleaves a carbon-carbon bond located one position away from the oxygen radical to form a stable carbonyl compound (like a ketone) and ejects a brand new radical (). The golden rule of -scission is simple: the bond that breaks will always be the one that produces the most stable radical possible.

Decoding the Molecules

Let's put these principles to the test with our four candidates:
Molecule 1: Features a benzyl group and a simple methyl group. The stable benzyl radical drives a concerted loss of . The resulting methoxy radical does not undergo -scission. This direct formation of and perfectly matches Pathway P.
Molecule 2: Features a phenyl group and a methyl group. The unstable phenyl radical forces a stepwise loss of . Again, the methoxy radical stays intact. This stepwise process without further fragmentation is Pathway S.
Molecule 3: Features a benzyl group, meaning a concerted start. The resulting bulky alkoxy radical must undergo -scission. It has a choice between ejecting a methyl radical or a benzyl radical. Since benzyl is vastly more stable, it breaks the bond to the benzyl group, yielding acetone and a benzyl radical. A concerted start followed by -scission is Pathway Q.
Molecule 4: Features a phenyl group, meaning a stepwise start. The resulting cumyloxy radical undergoes -scission. It must choose between ejecting a phenyl radical or a methyl radical. Because a methyl radical is slightly more stable than a highly unstable phenyl radical, it ejects methyl, leaving behind acetophenone. A stepwise start followed by -scission is Pathway R.

The Final Verdict

By meticulously analyzing the stability of the radicals formed at every step, we have successfully mapped the thermal destiny of each peroxyester. The final matrix match is a testament to the elegant logic of organic reaction mechanisms.

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The major products obtained from the reactions in List-II are the reactants for the named reactions mentioned in List-I. Match List-I with List-II and choose the correct option.

List-I

(P)
Etard reaction
(Q)
Gattermann reaction
(R)
Gattermann-Koch reaction
(S)
Rosenmund reduction

List-II

(1)
Acetophenone
(2)
Toluene
(3)
Benzene
(4)
Aniline
(5)
Phenol