Analyzing the Setup
Imagine you have a cylinder filled with a diatomic ideal gas, like oxygen or nitrogen. The gas is initially at a temperature Ti and occupies a volume Vi. Now, a piston rapidly compresses this gas to a mere 321 of its original volume. Because this compression happens so quickly, there is no time for heat to escape to the surroundings. This makes the process adiabatic.
We are told that the final temperature becomes aTi, and our mission is to find the value of this multiplier, a.
The Master Equation
For an adiabatic process involving an ideal gas, the relationship between temperature and volume is governed by the equation:
TVγ−1=constant
This means that the product of temperature and volume raised to the power of γ−1 remains the same throughout the process. We can write this for our initial and final states as:
TiViγ−1=TfVfγ−1
Before we can use this equation, we need to figure out the value of γ (the adiabatic index) for our gas. We know the gas is diatomic. At normal temperatures, a diatomic molecule has 5 degrees of freedom (3 translational and 2 rotational). The formula for γ is:
γ=1+f2
Substituting f=5, we get:
γ=1+52=57=1.4
Therefore, the exponent in our equation, γ−1, is simply 1.4−1=0.4.
Substituting and Solving
Now, let's plug everything we know into our master equation. We substitute γ−1=0.4, Tf=aTi, and Vf=32Vi:
TiVi0.4=(aTi)(32Vi)0.4
Look closely at this equation. The terms Ti and Vi0.4 appear on both sides. This is the beauty of such physics problems—the initial unknown variables often cancel out! Let's divide both sides by TiVi0.4:
1=a(321)0.4
To isolate a, we rearrange the equation:
a=(32)0.4
Final Calculation
All that's left is a bit of arithmetic. Let's convert the decimal exponent into a fraction to make it easier to handle:
0.4=104=52
So, we need to evaluate (32)52. We know that 32 is 2 raised to the power of 5 (25=32). Let's substitute this in:
a=(25)52
When you raise a power to a power, you multiply the exponents. The 5 in the numerator and the 5 in the denominator cancel each other out perfectly:
a=22=4
And there we have it! The value of a is 4. This means the temperature of the gas quadrupled during the compression. This dramatic rise in temperature is exactly how a diesel engine ignites its fuel without a spark plug—pure adiabatic compression!