Sigma Percentile
JEE Main 2021
LEVELJEE Main

Animated Solution for Chemistry - Coordination Compounds: The denticity of an organic ligand, biuret is

Select Answer:

Visualized Solution

  • Biuret is an organic compound with the chemical formula .

  • The oxygen atoms of the carbonyl () groups act as electron pair donors.

  • Biuret coordinates to a central metal ion through its two oxygen atoms, forming a stable six-membered chelate ring.

  • Denticity is the number of donor atoms binding to the metal.
  • For biuret, denticity .

The Sigma Insight: Nomenclature, Isomerism, Importance and Werner's Theory

Solution Diagram

Understanding Ligands and Denticity

In the fascinating world of coordination chemistry, a ligand is an ion or molecule that binds to a central metal atom to form a coordination complex. The binding occurs when the ligand donates one or more pairs of electrons to the metal's empty orbitals.
The term denticity (derived from the Latin word dentis, meaning tooth) refers to the number of donor atoms in a single ligand that bind to the central metal. Think of it as the number of 'bites' a ligand takes on the metal. If a ligand binds through one atom, it's monodentate; if through two, it's bidentate, and so on.

The Structure of Biuret

To determine the denticity of biuret, we first need to understand its chemical structure. Biuret is an organic compound formed by the condensation of two molecules of urea, resulting in the chemical formula .
Visually, it consists of two amide groups linked together by a central nitrogen atom. This creates a symmetrical molecule with multiple potential donor atoms: three nitrogen atoms and two oxygen atoms.

Identifying the Donor Sites

While it might be tempting to think the nitrogen atoms act as the donors (since ammonia is a classic ligand), the reality of biuret's coordination is different. The lone pairs on the nitrogen atoms are involved in resonance with the adjacent carbonyl () groups, making them less available for donation to a metal.
Instead, the oxygen atoms of the two carbonyl groups are the primary donor sites. They are rich in electron density and are perfectly positioned spatially. When a metal ion approaches, biuret wraps around it, using its two oxygen atoms to form two coordinate covalent bonds.
This specific binding mode creates a highly stable six-membered chelate ring (comprising the metal, two oxygens, two carbons, and the central nitrogen). Because a single biuret molecule uses exactly two donor atoms to bind to the metal, it is classified as a bidentate ligand. Therefore, the denticity of biuret is 2.

Similar Questions

JEE Main 2021
LEVELJEE Main

1 mol of an octahedral metal complex with formula on reaction with excess of gives 1 mol of . The denticity of ligand is .........

JEE Main 2019
LEVELJEE Main

The following ligand is

(A)
hexadentate
(B)
tetradentate
(C)
bidentate
(D)
tridentate
JEE Main 2020
LEVELJEE Main

The total number of coordination sites in ethylenediaminetetraacetate [EDTA] is ... .

LEVELJEE Main

How many EDTA (ethylenediamine tetraacetic acid) molecules are required to make an octahedral complex with a Ca ion?

(A)
Six
(B)
Three
(C)
One
(D)
Two
JEE Main 2019
LEVELJEE Main

The coordination numbers of Co and Al in and , respectively, are (en = ethane-1, 2-diamine)

(A)
5 and 3
(B)
3 and 3
(C)
6 and 6
(D)
5 and 6
JEE Main 2026
LEVELJEE Advanced

Consider that the coordinating atoms of the ligands in and octahedral complexes are at the vertices of an octahedron. The sum of total number of the triangular faces in both the complexes having one N atom and two Cl atoms at their corners is ____.

JEE Main 2017
LEVELJEE Main

On treatment of of solution of with excess of ; ions are precipitated. The complex is

(A)
(B)
(C)
(D)
LEVELJEE Main

The coordination number and the oxidation state of the element 'E' in the complex (where (en) is ethylene diamine) are, respectively

(A)
6 and 2
(B)
4 and 2
(C)
4 and 3
(D)
6 and 3
JEE Advanced 2015
LEVELJEE Main

In the complex acetylbromidodicarbonylbis(triethylphosphine)iron(II), the number of Fe–C bond(s) is-

JEE Main 2021
LEVELJEE Main

The correct structures of trans-[NiBr_2(PPh_3)_2] and meridonial-[Co(NH_3)_3(NO_2)_3], respectively are

(A)
(B)
(C)
(D)