Sigma Percentile
JEE Advanced 1988
LEVELJEE Advanced

Animated Solution for Physics - Rotational Motion: A cylinder of mass and radius is resting on a horizontal platform (which is parallel to the - plane) with its axis fixed along the -axis and free to rotate about its axis. The platform is given a motion in the -direction given by . There is no slipping between the cylinder and platform. The maximum torque acting on the cylinder during its motion is ......... .

Visualized Solution

Visualizing the Setup

  • Cylinder with a fixed axis on a moving platform.

Platform Kinematics

  • Platform's position:

Differentiating for Acceleration

  • Velocity:
  • Acceleration:

Maximum Platform Acceleration

  • Maximum acceleration of platform:

The No Slipping Constraint

  • No slipping condition at contact point :

Relating Translation to Rotation

  • Acceleration of bottom point:

Maximum Angular Acceleration

  • Maximum angular acceleration:

The Torque Equation

  • Torque equation:

Substituting Values

  • Moment of inertia of a solid cylinder:

Final Answer

The Way Forward

  • Friction force:

The Sigma Insight: Rolling Motion

Solution Diagram

The Setup

A Fixed Axis and a Restless Platform
Imagine a solid cylinder resting peacefully on a horizontal platform. But there is a crucial twist in this setup: the central axis of the cylinder is completely fixed in space. It cannot translate left or right; it is only free to spin about its own axis.
Meanwhile, the platform beneath it is not sitting still. It is oscillating back and forth in the -direction, executing Simple Harmonic Motion (SHM) described by the equation . The problem also explicitly states that there is no slipping between the cylinder and the platform. This means the friction between them is strong enough to force the cylinder to spin in perfect sync with the platform's back-and-forth motion. Our goal is to find the maximum torque acting on this cylinder.

Kinematics of the Platform

Riding the Harmonic Wave
To understand the forces and torques at play, we first need to understand the acceleration of the platform. Since the platform is driving the rotation of the cylinder, its acceleration is the root cause of the torque.
We start with the position of the platform:
To find the velocity, we take the first derivative with respect to time:
Taking the derivative one more time gives us the acceleration of the platform, :
Because the cosine function fluctuates between and , the maximum magnitude of this acceleration is simply the amplitude of the acceleration wave:

The "No Slipping" Constraint

Bridging Translation and Rotation
Here is where the physics gets beautiful. The "no slipping" condition is the bridge that connects the linear motion of the platform to the rotational motion of the cylinder.
No slipping means that the point on the cylinder that is in direct contact with the platform must have the exact same velocity and acceleration as the platform itself. Let's call this contact point .
Because the cylinder's central axis is fixed, point cannot have any translational acceleration of the center of mass. Its entire acceleration comes purely from the rotation of the cylinder. If the cylinder has an angular acceleration , the tangential acceleration of point is given by .
Equating the acceleration of the cylinder's bottom point to the platform's acceleration, we get our master constraint equation:
To find the maximum torque, we need the maximum angular acceleration. Using our constraint equation, we can write:

Dynamics of the Cylinder

The Torque Equation
Now we turn to Newton's Second Law for Rotation. The torque acting on a rigid body is equal to its moment of inertia multiplied by its angular acceleration :
To find the maximum torque, we simply use the maximum angular acceleration we just derived:
We know that for a uniform solid cylinder rotating about its central geometric axis, the moment of inertia is:

The Final Calculation

Bringing It All Together
We are now ready for the final substitution. Let's plug our expressions for and into the torque equation:
Notice how elegantly the math simplifies. One factor of in the numerator cancels out with the in the denominator, leaving us with:
This is our final answer.

The Way Forward

What About Friction?
It is always a great habit to ask what is actually providing this torque. In this setup, the only horizontal force acting on the cylinder is the static friction from the platform. Since this friction acts at a distance from the fixed axis, the torque is .
If we wanted to find the maximum friction force required to prevent slipping, we could simply divide our maximum torque by :
This tells us exactly how rough the platform needs to be to ensure the cylinder dances perfectly to its harmonic tune!

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