Sigma Percentile
JEE Main 2021 (March)
LEVELBoard

Animated Solution for Mathematics - Statistics: Consider three observations a, b and c such that . If the standard deviation of is , then which of the following is true?

Select Answer:

Visualized Solution

Problem Setup

  • Given observations:
  • Constraint:
  • Standard Deviation of is

Shift of Origin Property

  • Property: Standard Deviation is independent of the change of origin.
  • Adding or subtracting a constant does not change the spread of data.
  • Therefore,

Calculating the Mean

  • Let's find the mean of the original observations .
  • Formula:

Applying the Constraint

  • Substitute the given condition into the mean formula.

The Variance Formula

  • Variance is the square of Standard Deviation:
  • Formula:
  • For our data:

Substituting the Mean

  • Substitute into the variance equation.

Expanding the Squared Term

  • Square the mean term:

Clearing Denominators

  • To eliminate fractions, multiply the entire equation by the LCM, which is .

Simplifying the Equation

  • Expand the bracket:
  • Combine the terms:

Final Rearrangement

  • Rearrange to solve for to match the given options.
  • Move to the left and to the right:
  • Factor out :

The Sigma Insight: Variance and Standard Deviation

Analyzing the Setup

We are given three observations: , , and , subject to the constraint . We are also given that the standard deviation of the set is .
The first step is to recognize a fundamental property of statistics: standard deviation is a measure of dispersion, not location. Shifting every data point by a constant does not change the distance between the points.
Therefore, the standard deviation of is identical to the standard deviation of . We have effectively simplified the problem to finding the relationship between , and for the original set.

Calculating the Mean

Let the mean of the set be . Using our constraint , we substitute with in the numerator.
The mean simplifies to:

The Master Equation

We now invoke the variance formula, where the variance is the square of the standard deviation ():
Substituting our specific values into this formula, we obtain:
Expanding the square term, we get:

Final Algebraic Reduction

To clear the denominators, we multiply the entire equation by :
Expanding the bracket yields:
Combining the terms, we arrive at:
Rearranging to solve for , we find the final relationship:

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