Analyzing the Setup
We are given three observations: a, b, and c, subject to the constraint b=a+c. We are also given that the standard deviation of the set {a+2,b+2,c+2} is d.
The first step is to recognize a fundamental property of statistics: standard deviation is a measure of dispersion, not location. Shifting every data point by a constant does not change the distance between the points.
Therefore, the standard deviation of {a+2,b+2,c+2} is identical to the standard deviation of {a,b,c}. We have effectively simplified the problem to finding the relationship between a,b,c, and d for the original set.
Calculating the Mean
Let the mean of the set be xˉ=3a+b+c. Using our constraint b=a+c, we substitute a+c with b in the numerator.
The mean simplifies to:
xˉ=3b+b=32b
The Master Equation
We now invoke the variance formula, where the variance is the square of the standard deviation (
d2):
d2=n∑xi2−(xˉ)2
Substituting our specific values into this formula, we obtain:
d2=3a2+b2+c2−(32b)2
Expanding the square term, we get:
d2=3a2+b2+c2−94b2
Final Algebraic Reduction
To clear the denominators, we multiply the entire equation by
9:
9d2=3(a2+b2+c2)−4b2
Expanding the bracket yields:
9d2=3a2+3b2+3c2−4b2
Combining the
b2 terms, we arrive at:
9d2=3a2+3c2−b2
Rearranging to solve for
b2, we find the final relationship:
b2=3(a2+c2)−9d2