Sigma Percentile
JEE Main 2020
LEVELJEE Main

Animated Solution for Chemistry - Chemical Kinetics: Consider the following reactions , The order of the above reactions are and , respectively. The following graph is obtained when vs are plotted :

Select Answer:

Visualized Solution

\text{Analyzing the Graph}

  • \text{The graph plots } \log[\text{rate}] \text{ versus } \log[\text{conc.}] \text{ for four different reactions.}

\text{Rate Law Equation}

  • \text{For an } n^{\text{th}} \text{ order reaction:}
  • \text{Rate} = k [\text{conc.}]^n

\text{Logarithmic Transformation}

  • \text{Taking logarithm on both sides:}
  • \log(\text{Rate}) = \log(k [\text{conc.}]^n)
  • \log(\text{Rate}) = \log k + n \log[\text{conc.}]

\text{Equation of a Straight Line}

  • \text{Comparing with } y = mx + c:
  • y = \log(\text{Rate})
  • x = \log[\text{conc.}]
  • m = n \text{ (Slope = Order)}
  • c = \log k \text{ (y-intercept)}

\text{Comparing Slopes}

  • \text{From the graph, the steepness (slope) follows the order:}
  • \text{Slope}_D > \text{Slope}_B > \text{Slope}_A > \text{Slope}_C

\text{Final Conclusion}

  • \text{Since Slope } = \text{ Order } (n):
  • n_D > n_B > n_A > n_C
  • \text{Therefore, } d > b > a > c

\text{The Way Forward}

  • \text{What if the lines had different y-intercepts?}
  • \text{Different intercepts } \implies \text{ Different rate constants } (k).

The Sigma Insight: Order and Molecularity

Solution Diagram

The Graphical Puzzle

Imagine you are presented with a graph where multiple lines shoot upwards from a single point on the y-axis. The y-axis represents the logarithm of the reaction rate, , and the x-axis represents the logarithm of the concentration, . We have four different reactions labeled A, B, C, and D.
Notice how all four lines start from the exact same point on the y-axis but rise with different steepness. Our goal is to determine the order of these reactions based purely on this visual information. To decode this, we need to bridge the gap between the visual graph and the fundamental mathematics of chemical kinetics.

The Master Equation

To understand this graph, we must start with the fundamental rate law. For any general reaction of order , the rate is given by the equation:
Here, is the rate constant, and is the order of the reaction. However, our graph is plotted in terms of logarithms. Therefore, we need to transform our master equation into a logarithmic format. By taking the logarithm on both sides, we get:
Using the standard properties of logarithms, where and , we can expand the right side:

The Logarithmic Transformation

Does this new equation look familiar? It perfectly matches the standard equation of a straight line, . Let's map the variables:
- corresponds to - corresponds to - (the y-intercept) corresponds to - (the slope) corresponds to , the order of the reaction.
This mapping is a powerful revelation! The y-intercept is , which explains why all lines start from the exact same point on the y-axis: all four reactions share the same rate constant . Most importantly, the slope is exactly equal to , the order of the reaction.

Reading the Slopes

So, the secret is out! The slope of the line directly gives us the order of the reaction. Now, let's look at the graph again and compare the steepness of the lines.
Which line is the steepest? Line D has the maximum slope, followed by B, then A, and finally C has the least slope. Mathematically, we can write this as:
Since the slope is equal to the order (), the reaction with the highest slope will have the highest order. Therefore, the order is greater than , which is greater than , which is greater than :
This perfectly matches option (d). Always remember, in such graphical questions, the slope and the intercept hold the keys to unlocking the physical constants of the reaction!

Similar Questions

JEE Main 2019
LEVELJEE Main

The given plots represent the variation of the concentration of a reaction with time for two different reactions (i) and (ii). The respective orders of the reactions are

(A)
1, 1
(B)
0, 2
(C)
0, 1
(D)
1, 0
LEVELBoard

For a reaction , rate is given by , hence the order of the reaction is

(A)
3
(B)
2
(C)
1
(D)
0
JEE Main 2021
LEVELJEE Main

For the following graphs Choose from the options given below, the correct one regarding order of reaction is

(A)
(B) zero order (C) and (E) first order
(B)
(A) and (B) zero order (E) first order
(C)
(B) and (D) zero order (E) first order
(D)
(A) and (B) zero order (C) and (E) first order
JEE Main 2020
LEVELJEE Main

The results given in the below table were obtained during kinetic studies of the following reaction : X and Y in the given table are respectively

(A)
0.4, 0.4
(B)
0.4, 0.3
(C)
0.3, 0.4
(D)
0.3, 0.3
LEVELBoard

Consider following two reactions, and are expressed in terms of molarity () and time () as

(A)
(B)
(C)
(D)
JEE Main 2019
LEVELJEE Main

For the following reaction, When concentration of both ( and ) becomes double, then rate of reaction increases from to . When concentration of only is doubled, the rate of reaction increases from to . Which of the following is true?

(A)
The whole reaction is of 4th order
(B)
The order of reaction w.r.t. is one
(C)
The order of reaction w.r.t. is 2
(D)
The order of reaction w.r.t. is 2
JEE Main 2019
LEVELJEE Main

For the reaction, , the values of initial rate at different reactant concentrations are given in the table below. \begin{array}{|c|c|c|} \hline \mathbf{[A]} \text{ (mol L}^{-1}\text{)} & \mathbf{[B]} \text{ (mol L}^{-1}\text{)} & \text{\textbf{Initial rate}} \text{ (mol L}^{-1}\text{s}^{-1}\text{)} \\ \hline 0.05 & 0.05 & 0.045 \\ 0.10 & 0.05 & 0.090 \\ 0.20 & 0.10 & 0.72 \\ \hline \end{array} The rate law for the reaction is

(A)
rate =
(B)
rate =
(C)
rate =
(D)
rate =
JEE Main 2019
LEVELJEE Main

The following results were obtained during kinetic studies of the reaction; \begin{array}{cccc} \hline \text{Experiment} & \text{[A] (mol L}^{-1}\text{)} & \text{[B] (mol L}^{-1}\text{)} & \text{Initial rate (mol L}^{-1} \text{min}^{-1}\text{)} \\ \hline \text{I.} & 0.10 & 0.20 & 6.93 \times 10^{-3} \\ \text{II.} & 0.10 & 0.25 & 6.93 \times 10^{-3} \\ \text{III.} & 0.20 & 0.30 & 1.386 \times 10^{-2} \\ \hline \end{array} The time (in minutes) required to consume half of is

(A)
5
(B)
10
(C)
100
(D)
1
JEE Main 2021
LEVELJEE Main

The following data was obtained for chemical reaction given below at 975 K. The order of the reaction with respect to NO is \dots\dots . [Integer answer]

JEE Advanced 2014
LEVELJEE Main

For the elementary reaction , the rate of disappearance of increases by a factor of upon doubling the concentration of . The order of the reaction with respect to is

(A)
(B)
(C)
(D)