Sigma Percentile
JEE Advanced 2016
LEVELJEE Advanced

Animated Solution for Physics - Electrostatics: Comprehension Passage

Consider an evacuated cylindrical chamber of height having rigid conducting plates at the ends and an insulating curved surface as shown in the figure. A number of spherical balls made of a light weight and soft material and coated with a conducting material are placed on the bottom plate. The balls have a radius . Now, a high voltage source (HV) connected across the conducting plates such that the bottom plate is at and the top plate at . Due to their conducting surface, the balls will get charge, will become equipotential with the plate and are repelled by it. The balls will eventually collide with the top plate, where the coefficient of restitution can be taken to be zero due to te soft nature of the material of the balls. The electric field in the chamber can be considered to be that of a parallel plate capacitor. Assume that there are no collisions between the balls and the interaction between them is negligible. (Ignore gravity)
Question 1:

Which one of the following statement is correct?

Select Answer:

Question 2:

The average current in the steady state registered by the ammeter in the circuit will be

Select Answer:

Visualized Solution

  • Bottom plate potential:
  • Top plate potential:

  • Potential of the ball at the bottom plate:
  • Capacitance of a spherical ball:
  • Charge acquired:

  • Potential difference between plates:
  • Distance between plates:
  • Uniform electric field:

  • Electrostatic force:

  • Acceleration:

  • Kinematic equation:
  • Time taken to reach the top plate:
  • Substituting :

  • Current is the rate of charge transfer:
  • Substitute and

  • At the top plate (), the ball acquires a negative charge: .
  • The electric field is upwards. Force on negative charge is downwards.
  • The ball is repelled back to the bottom plate.
  • Since is constant, is constant. Motion is oscillatory, not SHM ().

  • Consider the effect of air resistance on the terminal velocity and average current.

The Sigma Insight: Capacitance and Capacitors

Solution Diagram

Analyzing the Setup

Imagine this cylindrical chamber. The bottom plate is at a high positive potential, , and the top plate is at a negative potential, . The little conducting balls resting at the bottom will acquire a positive charge, and because like charges repel, they will be shot upwards towards the top plate!
Let's focus on just one ball. Since it's touching the bottom plate, its potential becomes . We know the capacitance of a small sphere is . So, the charge it picks up is simply its capacitance times the potential, which gives us:
Now, what's the electric field driving this ball? The chamber acts like a giant parallel plate capacitor. The total potential difference is , which is . Dividing this by the height gives us the uniform electric field inside the chamber:

The Master Equation

With the charge and electric field known, we can find the electrostatic force acting on the ball. The force is simply the charge times the electric field . This upward force is what propels the ball towards the top plate.
By Newton's second law, the acceleration is this force divided by the mass . Substituting our expressions for and , we get:
Notice carefully that the acceleration is directly proportional to the square of .
The ball starts from rest and travels a distance . Using the second equation of motion, , we can solve for the time of flight, :
When we plug in our acceleration, notice that is in the denominator inside the square root. So, the time is inversely proportional to .

Final Calculation

Finally, let's find the average current. Current is the total charge transported per unit time. For balls, it's times divided by :
Since the charge is proportional to , and the time is inversely proportional to , dividing them gives us a current that is proportional to ! A beautiful result.

Analyzing the Motion

Let's also answer the conceptual question. When a ball hits the top plate, the coefficient of restitution is zero, meaning it stops momentarily. However, it now touches the negative plate and acquires a negative charge!
The upward electric field now exerts a downward force on this negative charge, pushing it back to the bottom plate. So, it bounces back carrying the opposite charge. And since the force is constant, not proportional to displacement, it's an oscillatory motion, but not Simple Harmonic Motion.

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