Sigma Percentile
JEE Advanced 2016
LEVELJEE Advanced

Animated Solution for Physics - Electromagnetic Induction: A conducting loop in the shape of a right angled isosceles triangle of height 10 cm is kept such that the vertex is very close to an infinitely long conducting wire (see the figure). The wire is electrically insulated from the loop. The hypotenuse of the triangle is parallel to the wire. The current in the triangular loop is in counterclockwise direction and increased at a constant rate of . Which of the following statement(s) is (are) true? (2016 Adv.)

Select Answer:

* Multiple Correct

Visualized Solution

  • By the reciprocity theorem, mutual inductance is symmetric: .
  • It is easier to calculate by assuming a current in the straight wire and finding the flux through the loop.

  • Assume a steady current flows through the infinitely long straight wire.
  • The magnetic field at a perpendicular distance from the wire is:

  • Consider an elemental horizontal strip of the triangle at a distance from the wire, with thickness .
  • Since the vertex angle is , the width of the strip is .
  • The area of this strip is .

  • The differential magnetic flux through this strip is:
  • Integrating from to :

  • The mutual inductance is .
  • The induced EMF in the wire is .
  • Given and :

  • According to Lenz's Law, the induced current opposes the change in magnetic flux.
  • Since the loop's current is increasing, the induced current in the wire flows in a direction to repel the loop.
  • Thus, there is a repulsive force between the wire and the loop.

  • The magnetic field of the straight wire has perfect cylindrical symmetry.
  • Rotating the loop around the wire at a constant radius does not change the magnetic flux linkage.
  • Since , no additional EMF is induced.

The Sigma Insight: Self and Mutual Inductance

Solution Diagram

The Magic of Reciprocity

Imagine trying to calculate the magnetic flux passing through an infinitely long straight wire due to a triangular loop. It sounds like a mathematical nightmare! But physics offers us a beautiful shortcut: the Reciprocity Theorem of Mutual Inductance. This theorem states that the mutual inductance between two circuits is symmetric, meaning . Instead of tackling the complex field of the triangle, we can simply assume a steady current in the straight wire and calculate the flux it produces through the triangular loop.

Slicing the Triangle

Let's set up our geometry. The straight wire lies along the x-axis. The right-angled isosceles triangle has its vertex at the origin, extending downwards. The magnetic field produced by the wire at a distance is given by Ampere's Law: .
To find the total flux, we slice the triangle into horizontal elemental strips of thickness . Because the vertex angle is , the boundaries of the triangle are the lines and . Thus, at a depth , the width of the strip is exactly . The area of this strip is .

The Master Equation

Now, we calculate the small magnetic flux passing through this strip:
Notice how beautifully the terms cancel out! Integrating this from to the height of the triangle , we get the total flux:
The mutual inductance is simply .
Given that the current in the loop is changing at a rate of and the height , the induced EMF in the wire is:
This confirms that the magnitude of the induced EMF is indeed volts.

Lenz's Law and Repulsion

What about the force between them? Enter Lenz's Law. The induced current always acts to oppose the change in magnetic flux. Since the current in the loop is increasing, the induced current in the wire will flow in a direction that attempts to push the loop away, reducing the mutual flux linkage. This results in a repulsive force between the wire and the loop.

The Symmetry of Rotation

Finally, consider rotating the loop around the wire. The magnetic field of a straight wire possesses perfect cylindrical symmetry. As the loop rotates at a constant radius, the magnetic field lines it cuts do not change, meaning the magnetic flux remains perfectly constant. Since the rate of change of flux is zero (), no additional EMF is induced during this rotation.

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